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OLEGan [10]
3 years ago
15

The acceleration of an object due to gravity is 32 feet per second squared. What is acceleration due to gravity in inches per se

cond squared?
Mathematics
2 answers:
makvit [3.9K]3 years ago
8 0
32 feet = 384 inches
Gwar [14]3 years ago
8 0

Answer:

384 inches per second squared.

Step-by-step explanation:

Using the conversion:

1 feet per second squared = 12 inches per second squared.

As per the statement:

The acceleration(a) of an object due to gravity is 32 feet per second squared

⇒a = 32 feet per second squared

We have to find a in inches per second squared.

Using above conversion;

1 feet per second squared = 12 inches per second squared

then;

32 feet per second squared = 384 inches per second squared.

Therefore, acceleration due to gravity in inches per second squared is, 384 inches per second squared.

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A sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters. Give a point est
xxTIMURxx [149]

Answer:

Point estimate for the population variance = 3.92 * 10^{-3} .

Step-by-step explanation:

We are given that a sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters ;

       X                       X - Xbar                                         (X-Xbar)^{2}

      1.13            1.13 - 1.188 = -0.058                                 3.364 * 10^{-3}

      1.15            1.15 - 1.188 = -0.038                                 1.444 * 10^{-3}    

      1.15            1.15 - 1.188 = -0.038                                 1.444 * 10^{-3}

      1.24           1.24 - 1.188 = 0.052                                 2.704 * 10^{-3}

      1.27           1.27 - 1.188 = 0.082                               <u>  6.724 * </u>10^{-3}<u>    </u>

                                                                    \sum (X-Xbar)^{2} <u>= 0.01568   </u>

Firstly, Mean of above data, Xbar = \frac{\sum X}{n} = \frac{1.15+1.24+1.15+1.27+1.13}{5} = 1.188

Point estimate of Population Variance = Sample variance

                                                               = \frac{\sum (X-Xbar)^{2}}{n-1} = \frac{0.01568}{4} = 3.92 * 10^{-3} .

Therefore, point estimate for the population variance = 3.92 * 10^{-3} .

       

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