Answer:
see below
Step-by-step explanation:
We need to find the diameter of the square
We can find this using the Pythagorean theorem
a^2+b^2 = c^2 where the legs are 7 and 7 and the diameter is c
7^2 +7^2 = c^2
49+49 = c^2
98 = c^2
Taking the square root of each side
sqrt(98) = sqrt(c^2)
9.899494937 = c
Since 9.9 is less than 11 which is the diameter of the circle it will never touch the circle.
Since the longest part of the square is less than the diameter of the circle, the square will fit inside the circle without touching
<span>An event with probability 0 never occurs. An event with probability 1 occurs on every trial</span>
1= -6
2= -5
3= -4
4= -3
5= 0
6= 3
2=2*1,1*2
24=1*24,2*12,6*4,3*8
19=2*8+3
2x²+19x+24
(2x+3)(x+8)
or
2x(x+8)+3(x+8)
2x²+16x+3x+24
2x²+19x+24
