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3 years ago

What decimal is equivalent to each fraction?

Mathematics

1 answer:

Maksim231197 [3]3 years ago

3 0

1/6 = 0.16 with a line over the 6 because it is repeating

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Which is an example of a short-term investment?

katovenus [111]

Checking account is a short term investment

8 0

2 years ago

Correct answers only please! If you don't know the answer, then please don't guess or say what you think it is.

hammer [34]

Answer:

The option "C" is correct

#in my opinion#

Step-by-step explanation:

The size of a screen is generally measured diagonally.

Thus to find the diagonal length,

we take help from Pythagoras theorem

$i.e. \\ {h}^{2} = {b}^{2} + {p}^{2}$

where h (hypotenuse) is the diagonal length, b (base) is the length of horizontal side, and p (perpendicular) is the length of the vertical side of the TV,

THUS the diagonal length or hypotenuse

$h = \sqrt{ {b}^{2} + {p}^{2} } \\ \: = \sqrt{1024 + 324} \\ \: = \sqrt{1348} \\ \: = 36.7 \: (= aprox \: 37)$

3 0

3 years ago

Someone help plz make sure it’s right and please no websites plz

MAVERICK [17]

Hoped this helped. I learned this as well. It’s really easy. You’ll get it.

5 0

3 years ago

Read 2 more answers

Factor the expression:<br><br> -\lambda ^{3}+4\lambda ^{2}+4\lambda -16

Anit [1.1K]

Answer:

$-(\lambda -4)(\lambda -2)(\lambda +2)$

Step-by-step explanation:

What we want to fator is:

$-\lambda^3 + 4 \lambda^2 + 4\lambda - 16$

There is no common factor, but let's factor it by grouping. The first two addends can be factor as follows:

$-\lambda^3 + 4 \lambda^2 = \lambda^2(-\lambda + 4) = -\lambda^2(\lambda - 4)$

the second addends can be factor as well:

$4\lambda - 16 = 4(\lambda- 4)$ .

Then our original expression can be rewritten like

$-\lambda^3 + 4 \lambda^2 + 4\lambda -16=\lambda^2(\lambda - 4) + 4(\lambda - 4)$

And here the $(\lambda-4)$ is the common factor!

$-\lambda^2(\lambda - 4) + 4(\lambda - 4) = (\lambda - 4)(-\lambda^2 + 4)$

Finally, we can factor the quadratic expression as a difference of squares $-\lambda^2 + 4 = 4 - \lambda^2 = (2+\lambda)(2-\lambda)$

Ant we get

$(\lambda - 4)(-\lambda^2 + 4)= (\lambda - 4)(\lambda + 2)(2-\lambda)$

now, we can extract the negative sign from $(2-\lambda)$ , and we get

$-(\lambda -4)(\lambda -2)(\lambda +2)$ .

3 0

3 years ago

the expenses of a tea party are partly constant and partly vary directly with the number of guest.when there are 60 guest,the ex

Hatshy [7]

Answer:

$6300

Step-by-step explanation:

Using the equation of y=mx+c where c is constant, m is gradient then the two situations can be written as

2100=60x+c Equation 1

4800=150x+c Equation 2

Subtracting the terms of equation 1 from 2

(150-60)x=$4800-$2100

90x=$2700

x=$30

Substituting the value x into equation 1

60($30)+c=$2100

c=$2100-$1800=$300

c=$300

For 200 guests

y=200($30)+$300

y=$6000+$300=$6300

4 0

2 years ago