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Vesna [10]
3 years ago
8

PLS HELP!!

Mathematics
1 answer:
Arlecino [84]3 years ago
6 0
It would be A 15 because you will have to take off 10 to make a square and then divide by 4 to get a square
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How do you turn 140 into a fraction
Nimfa-mama [501]
140/1

because anything divided by 1 is itself, and a fraction is just the numberator divided by the denominator.
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3 years ago
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A bag with 8 marbles has 8 yellow marbles. A marble is chosen from the bag at random. What is the probability that it is yellow?
konstantin123 [22]

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Step-by-step explanation:

8 yellow / 8 total = 8/8 = 1

8 0
2 years ago
A father is 28 years older than his son. in 8 years time he will be 3 times as old as his son. how old is the father now?
mariarad [96]

Answer:

34 years

Step-by-step explanation:

f = s + 28          Eq. 1

f+8 = 3(s+8)      Eq. 2

f = father age

s = son age

replacing Eq. 1 on Eq. 2

(s+28) + 8 = 3(s+8)

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s + 36 = 3s + 24

36 - 24 = 3s - s

12 = 2s

12/2 = s

s = 6

from the Eq. 1

f = 6 + 28

f = 34

Check

from the Eq. 2

34+8 = 3(6+8)

42 = 3*14

6 0
2 years ago
Determine if the statement is always, sometimes or never true.
Reika [66]
A always a euilateral triangle is a regular polygon
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3 years ago
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Express the complex number in trigonometric form. <br><br> 3 - 3i<br><br><br> radians pls
belka [17]
\bf \begin{array}{llll}&#10;3&-&3i\\&#10;\uparrow &&\uparrow \\&#10;a&&b&#10;\end{array}\qquad &#10;\begin{cases}&#10;r=\sqrt{a^2+b^2}\\&#10;\theta=tan^{-1}\left( \frac{b}{a} \right)&#10;\end{cases}\\\\&#10;-----------------------------\\\\&#10;r=\sqrt{3^2+3^2}\implies r=\sqrt{18}\implies r=3\sqrt{2}&#10;\\\\\\&#10;tan(\theta)=\cfrac{3}{3}\implies tan(\theta)=1\implies \measuredangle \theta=tan^{-1}(1)&#10;\\\\\\&#10;\measuredangle \theta=\frac{\pi }{4}\impliedby \textit{reference angle}

now, b is -3, and a is 3
or in rectangular if you wish, y = -3 and x = 3....  on what quadrant is "y" negative and "x" positive?  well, the 4th quadrant
so, using our reference angle, that'd be \bf \cfrac{7\pi }{4}\quad or \quad -\cfrac{\pi }{4}

so, let's use the first one

\bf (3,3i)\implies &#10;\begin{array}{llll}&#10;r[cos(\theta)+i\ sin(\theta)]\\\\&#10;3\sqrt{2}\left[ cos\left( \frac{7\pi }{4} \right)+i\ sin\left( \frac{7\pi }{4} \right) \right]&#10;\end{array}


5 0
3 years ago
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