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igomit [66]
3 years ago
8

Line segment YV of rectangle YVWX measures 24 units.

Mathematics
1 answer:
Anna [14]3 years ago
7 0

Answer: 8√3

<u>Step-by-step explanation:</u>

ΔXVW is a 30°-60°-90° triangle. This special triangle has corresponding sides of lengths: b - b√3 - 2b.  So,

VW = b

XW = b√3

XV = 2b

Since, YV = 24, then XW = 24 and we stated above that XW = b√3. So,

24 = b√3

\frac{24}{\sqrt{3}} = \frac{b\sqrt{3}}{\sqrt{3}}

\frac{24}{\sqrt{3}} = b

\frac{24}{\sqrt{3}}(\frac{\sqrt{3}}{\sqrt{3}}) = b

\frac{24\sqrt{3}}{3} = b

8√3 = b

We are looking for side YX which is congruent (equal) to VW and we stated above that VW = b, So, VW = 8√3

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A company makes windows for use in homes and commercial buildings. The standards for glass thickness call for the glass to avera
guajiro [1.7K]

The question is incomplete. The complete question follows.

A company makes windows for use in homes and commercial builidings. The standards for glass thickness call for the glass to average 0.325 inch with a standard deviation equal to 0.065 inch. Suppose a random sample of n=44 windows yield a sample mean of 0.337 inch. Complete parts a and b.

a. What is the probability of x ≥ 0.337 if the windows meet the standards?

b. Based on your answer to part a, what would you conclude about the population of windows? Is it meeting the standards? (A result is unusual if it has a probability less than 0.05)

Answer and Step-by-step explanation: To answer this question, use <u><em>Central Limit Theorem</em></u>: it states regardless of the original population distribution, if the sample size is large enough, the sample mean distribution will approach a normal distribution.

The calculations for the CLT is given by normalizing the distribution, i.e.:

z=\frac{x-\mu}{\sigma/\sqrt{n} }

where

z is z-score

x is the sample mean

μ is population mean

σ is standard deviation of the population

n is the number of individuals in the sample

Calculating z-score for the window maker company:

z=\frac{0.337-0.325}{0.065/\sqrt{44} }

z=\frac{0.012}{0.0098}

z = 1.22

Using the z-score table, we found the probability:

P = 0.8888

As it is a "more than situation":

P(x≥0.337) = 1 - 0.8888

P(x≥0.337) = 0.1112  or 11.12%

a. Probability of x≥0.337 if the windows meet the standards is 11.12%.

b. Comparing results, probability of x≥0.337 is bigger than 0.05:

0.1112 > 0.05

So, we can conclude that the random sample of n=44 is meeting the standards estipulated.

7 0
3 years ago
A housekeeper was earning $9.50 an hour before a
Degger [83]

Answer:

raise = $0.76

new wage = $10.26 per hour

Step-by-step explanation:

8% in decimal form = 8/100 = 0.08

To find 8% of 9.50:  0.08 x 9.50 = 0.76

Therefore, the housekeeper's raise = $0.76

To calculate the amount she now earns after the raise, add the 8% rise to the initial value:

0.76 + 9.50 = $10.26

5 0
2 years ago
Ken went to the store for his mother. He spent $2.37 on groceries. His mother said he could spend 35¢ on candy. What was his cha
Sedbober [7]
The answer is 1.28 because you add 2.37+35 then subtract that from $5
3 0
3 years ago
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A dog is leashed to the corner of a house with a 20 ft long leash. How much running area does the dog have? Round your answer to
11111nata11111 [884]

Answer:

The dog's running area is approximately 942 feet².

Step-by-step explanation:

The dog is leashed to a fixed point, the leash has a length of 20 ft, therefore he can rotate around that point at the maximum distance equal to the length of the leash. This pattern forms a circle, but there is an obstruction, which is the corner of the house. This obstruction takes an arc of the original circle, so the running area of the dog is the area of the whole circle minus the area of the arc formed by the corner of the house.

\text{dog's area} = \text{circle's area} - \text{arc's area}\\\\\text{dog's area} = pi*(20^2) - \frac{90}{360}*pi*(20^2)\\\\\text{dog's area} = \frac{270}{360}*pi*(400)\\\\\text{dog's area} = 942.477\text{ feet}^2

The dog's running area is approximately 942 feet².

3 0
3 years ago
Please help solve picture
coldgirl [10]

UGH I think I did this before but I totally forgot how to do it. Give me a minute to do some research and remember because I'm about 79% sure I know how to do this!

6 0
3 years ago
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