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Lostsunrise [7]

3 years ago

11

it will cost $285 to charter a bus for a class trip. the class treasurer says that there is $60 in the class treasury. the 20 st

udents going on the trip agree to make up the difference. write and solve an equation to find how much each students will pay

2 answers:

dalvyx [7]3 years ago

4 0

(285-60)/20
Which is $11.25 per child

myrzilka [38]3 years ago

3 0

(285-60) divided by 20 =11.25

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How can you prove a triangle is a right triangle?

Darina [25.2K]

Your answer would be option 2. Use the slope formula to see if any sides are perpendicular. This is because a right triangle must have 2 perpendicular sides that form a 90° angle for it to be a right triangle, so finding these would prove it.
I hope this helps!

6 0

2 years ago

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

prohojiy [21]

Answer:

$2.25$

Step-by-step explanation:

$(6x^{-2})^2(0.5x)^4\\\\=(6^2(x^{-2})^{2})(0.5^4x^4)\ \ \ \ \ \ \ \ \ \ \ \ \ as\ (ab)^m=a^mb^m\\\\=36\times 0.5^4((x^{-2})^2x^4)\ \ \ \ \ \ \ \ \ \ as\ multiplication\ is\ associative\ a(bc)=(ab)c\\\\=36\times 0.0625(x^{-4}x^4)\ \ \ \ \ \ \ \ \ \ \ as\ (x^m)^n=x^{mn}\\\\=(36\times 0.0625)(x^{-4+4})\ \ \ \ \ \ \ \ \ \ \ as\ x^mx^n=x^{m+n}\\\\=2.25x^0\\\\=2.25\ \ \ \ \ \ \ \ \ \ \ \ as\ x^0=1\\\\(6x^{-2})^2(0.5x)^4=2.25$

7 0

2 years ago

See attached picture, is there a way to enter equations or algebraic symbols?

coldgirl [10]

SOLUTIONS

Solve a given equations or algebraic symbols?

$\begin{gathered} f(x)=x^2+2x \\ g(x)=1-x^2 \end{gathered}$

(A)

$\begin{gathered} (f+g)(x)=(x^2+2x)+(1-x^2) \\ collect\text{ like terms} \\ x^2-x^2+2x+1 \\ (f+g)(x^)=2x+1 \end{gathered}$

(B)

$\begin{gathered} (f-g)(x)=(x^2+2x)-(1-x^2) \\ =x^2+2x-1+x^2 \\ =x^2+x^2+2x-1 \\ (f-g)(x)=2x^2+2x-1 \end{gathered}$

(C)

$\begin{gathered} fg(x)=(x^2+2x)(1-x^2) \\ =x^2-x^4+2x-2x^3 \\ fg(x)=-x^4-2x^3+x^2+2x \end{gathered}$

(D)

$\begin{gathered} \frac{f}{g}(x)=(x^2+2x)\div(1-x^2) \\ =\frac{x^2+2x}{1-x^2} \end{gathered}$

5 0

1 year ago

BCALLE can u help me please

Ksivusya [100]

17. RQ is the same as PS.
PS = -1 + 4x
RQ = 3x + 3
-1 + 4x = 3x + 3
4x = 3x + 4
x = 4
Now plug that into RQ.
3(4) + 3 = RQ
15 = RQ

18. Angles G and E are equal to each other.
G = 5x - 9
E = 3x + 11
5x - 9 = 3x + 11
5x = 3x + 20
2x = 20
x = 10
Plug that x into G.
5(10) - 9
41 = G

19. TE and EV are equal to each other.
TE = 4 + 2x
EV = 4x - 4
4 + 2x = 4x - 4
2x = 4x - 8
-2x = -8
x = 4
Plug that into TE.
4 + 2(4)
12 = TE

20. DB and BF are equal.
DB = 5x - 1
BF = 5 + 3x
5x - 1 = 5 + 3x
5x = 6 + 3x
2x = 6
x = 3
Plug that into DB.
5(3) - 1
14 = DB

4 0

3 years ago

W^2-8w-20 factor the polynomial.

Mademuasel [1]

Your answer would be (w+2)(w−10). If you want me to explain please don't hesitate to ask.

6 0

2 years ago

Read 2 more answers