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3 years ago

10

PLEEEEEEEEAAAAAAAAAAAASEEEEEEE HELP What is 1/7 as a decimal rounded to the nearest 100th

1 answer:

Elenna [48]3 years ago

4 0

It should be 0.14 if I’m not wrong

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Im h--> 0<br><br> ((Sqrt 9+h)-3)/h

Svetradugi [14.3K]

$\lim_{h \to 0} \frac{ \sqrt{9+h}-3}{h} = \frac{ \sqrt{9+0} -3}{0}= \frac{0}{0} \\ \lim_{h \to 0} \frac{ \sqrt{9+h}-3}{h}* \frac{ \sqrt{9+h}+3 }{ \sqrt{9+h} +3}= \\ = \lim_{h \to 0} \frac{9+h-9}{h( \sqrt{9+h} +3)} = \\ \lim_{n \to 0} \frac{h}{h( \sqrt{9+h}+3) }= \\ = \frac{1}{ \sqrt{9} +3}$ =
= 1/6

6 0

3 years ago

Are the expressions 0.85b-0.2b and 0.65b equivalent?

Savatey [412]

Hello!

0.85b-0.2b

0.65b

0.65b=0.65b

So these expressions are equivalent.

Hope it helps!

~Just a determined gal

#CarryOnLearning

$MysteriousNature$

5 0

3 years ago

Please please please help

algol [13]

Answer:

I think the answer is ten

3 0

3 years ago

Read 2 more answers

Subtract rational expression. <br> Show work please.

yan [13]

Given:

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}$

To find:

The simplified rational expression by subtraction.

Solution:

Let us factor $x^2-1$ . It can be written as $x^2-1^2$ .

$x^2-1^2=(x-1)(x+1)$ using algebraic identity.

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x+4}{x-1}-\frac{5}{(x+1)(x-1)}$

LCM of $x-1,(x+1)(x-1)=(x+1)(x-1)$

Make the denominators same using LCM.

Multiply and divide the first term by (x + 1) to make the denominator same.

$$=\frac{(x+4)(x+1)}{(x-1)(x+1)}-\frac{5}{(x-1)(x+1)}$

Now, denominators are same, you can subtract the fractions.

$$=\frac{(x+4)(x+1)-5}{(x-1)(x+1)}$

Expand $(x+4)(x+1)-5$ .

$$=\frac{x^2+4x+x+4-5}{(x-1)(x+1)}$

$$=\frac{x^{2}+5 x-1}{(x-1)(x+1)}$

$$\frac{x+4}{x-1}-\frac{5}{x^{2}-1}=\frac{x^{2}+5 x-1}{(x-1)(x+1)}$

6 0

3 years ago

12. A bucket contains 40 yellow golf balls and 30 white golf balls. You randomly choose a ball, hit it toward the flag, then ran

natima [27]

Answer:

1476

Step-by-step explanation:

Because

5 0

3 years ago