Question

Find the length of the missing side of the right triangle.​

Answer 1

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{13 \: \: units \: }}}}}$

Step-by-step explanation:

Perpendicular ( p ) = 5

Base ( b ) = 12

Hypotenuse ( h ) = ?

Finding the length of missing side

Using Pythagoras theorem

$\boxed{ \sf{ {h}^{2} = { p}^{2} + {b}^{2} }}$

plug the values

⇒$\sf{ {h}^{2} = {5}^{2} + {12}^{2} }$

Evaluate the power

⇒$\sf{ {h}^{2} = 25 + 144}$

Add the numbers : 25 and 144

⇒$\sf{ {h}^{2} = 169}$

Squaring on both sides

⇒$\sf{ \sqrt{ {h}^{2} } = \sqrt{169}}$

Calculate

⇒$\sf{ {h} = 13 \: units}$

Hope I helped!

Best regards! :D

Answer 2

Here you are trying to find the hypotenuse. So you would take
5^2 (five squared) plus 12^2 (twelve squared) and add them using the equation a^2+b^2= c^2. Now you square 5 and 12 to get 25 and 144. You add them together and get 169. Take the square root of 169 and c. The square root on c will cancel out the squared (to the power of two) part leaving you with just c. And the square root of 169 is 13. So c (the missing length) is 13. C=13.