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fomenos
3 years ago
14

What are the X intercepts for y = 4sin2x

Mathematics
1 answer:
Natali [406]3 years ago
4 0
To calculate x intercepts, make the y=0.

0 = 4sin(2x)

But I apologize I do not know how to calculate that so please look at the screenshot
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I really need help with this I’ll mark the most helpful answer as brainliest
allsm [11]

Answer: 118 degrees

Step-by-step explanation:

Angles on the opposite sides of rhombus will always be equal and the sum of all the angles of quadrilaterals are 360 degrees so we get the equation

2u - 70 + u + 52 + 2u - 70 + u + 52 = 360

6u - 36 = 360

6u = 396

u = 66

But, 66 is not the answer, as they want to find the angle D AKA u + 52 which is 66 + 52 = 118 degrees

8 0
3 years ago
What is the range of f(x)?<br> {xl-2 {x|-2 {yl-5 {yl-5 sy&lt;-1}
Bas_tet [7]

Answer:

-5≤y≤-1

Step-by-step explanation:

The range is the values that y takes

The smallest value of y is -5 and the largest value of y is -1

-5≤y≤-1

7 0
3 years ago
one fabric costs $15.00 for two yards. Another costs $37.50 for 5 yards. Do these fabrics have the same unit cost? explain
kondaur [170]
Yes they do becuase
$15 divided by 2 equals $7.50
Then you do 5 times $7.50 and your anwser is $37.50
They total unit cost for each is $7.50
6 0
3 years ago
CAN SOMEONE HELP ME WITH THIS I WILL GIVE BRAINLIEST TO THE CORRECT ANSWER
Harlamova29_29 [7]
45. X= 2/3x+11/6
46. X=7
47. X=-28/19
48.X=1/2
59. X=-4/3-2y/3
60.X=-1+y/2 or 1+y/2
6 0
3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3&#10;

has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
3 years ago
Read 2 more answers
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