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3 years ago

Hello! Is my answer correct?

Mathematics

2 answers:

Anit [1.1K]3 years ago

8 0

Your answer is incorrect because It doesn't mention the 1/4 in the equation so it is the second one.

My name is Ann [436]3 years ago

5 0

It is the third one, you are correct!!!!:)

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Fool me twice....................................................

Lady_Fox [76]

Fool me three times shame on both of us

4 0

2 years ago

What is the first step when rewriting y=6x^2+18x+14 in the form y=a(x-h)^2+k?

Grace [21]

<h3>Answer:</h3>

Factor 6 from the first two terms.

<h3>Step-by-step explanation:</h3>

By factoring out "a", you can better see what "h" needs to be.

y = 6(x^2 +3x) +14 . . . . 6 factored from first 2 terms
add the square of half the x-coefficient inside parentheses; add the opposite outside: y = 6(x^2 +3x +2.25) +14 -6(2.25)
rewrite as a square; combine the constants: y = 6(x+1.5)^2 +0.5

7 0

2 years ago

Which would be the best name for a function that takes the time of day and returns the numbers of coffee sold at a coffee shop?

konstantin123 [22]

Answer:

Coffee(time)

Step-by-step explanation:

A function's output variable will be:

output(input)

So we need to find the input variable and the output variable.

We know that when the time of day changes, we get a certain amount of coffee sold. This means that the amount of coffee sold is directly influenced by the time of day.

The time of day then becomes our input as the coffee sold relies on that number.

That leaves coffee sold as our output!

So the best name for a function in this scenario is Coffee(time).

Hope this helped!

3 0

3 years ago

(ED. 21) Analytic Geometry Unit Test..... #3 Which point is a solution of x2 + y2 > 49 and y ≤ –x2 – 4?

sdas [7]

Answer:

We want to find a solution of the system:

x^2 + y^2 > 49

y ≤ –x^2 – 4

Here we do not have any options, so let's try to find a general solution.

First, we can remember that the equation of a circle centered in the point (a, b) and of radius R is:

(x - a)^2 + (y - b)^2 = R^2

If we look at our first inequality, we can write it as:

x^2 + y^2 > 7^2

So the solutions of the first inequality are all the points that are outside (because the symbol used is >) of the circle of radius R = 7 centered in the origin.

From the other equation, we would get:

y ≤ –x^2 – 4

This is parabola, anything that is in the graph of the parabola or below will be a solution for this inequality.

Then the solutions of the system, are the ones that are in the region of solutions for both inequalities.

You can see the graph below, where both regions are graphed. The intersection of these regions is the region of the solutions for the system of inequalities:

by looking at the graph, we can see a lot of points that are solutions, like:

(0, -10)

(0, -15)

(2, -10)

etc.

8 0

3 years ago

Someone help me please!

andriy [413]

Answer:

To solve the first inequality, you need to subtract 6 from both sides of the inequality, to obtain 4n≤12. This can then be cancelled down to n≤3 by dividing both sides by 4. To solve the second inequality, we first need to eliminate the fraction by multiplying both sides of the inequality by the denominator, obtaining 5n>n^2+4. Since this inequality involves a quadratic expression, we need to convert it into the form of an^2+bn+c<0 before attempting to solve it. In this case, we subtract 5n from both sides of the inequality to obtain n^2-5n+4<0. The next step is to factorise this inequality. To factorise we must find two numbers that can be added to obtain -5 and that can be multiplied to obtain 4. Quick mental mathematics will tell you that these two numbers are -4 and -1 (for inequalities that are more difficult to factorise mentally, you can just use the quadratic equation that can be found in your data booklet) so we can write the inequality as (n-4)(n-1)<0. For inequalities where the co-efficient of n^2 is positive and the the inequality is <0, the range of n must be between the two values of n whereby the factorised expresion equals zero, which are n=1 and n=4. Therefore, the solution is 1<n<4 and we can check this by substituting in n=3, which satisfies the inequality since (3-4)(3-1)=-2<0. Since n is an integer, the expressions n≤3 and n<4 are the same. Therefore, we can write the final answer as either 1<n<4, or n>1 and n≤3.

5 0

3 years ago