Answer:
see below
Step-by-step explanation:
First, she should subtract 6 from both sides of the inequality. This makes it so that the x terms are on one side and the non-x terms are on the other side so she can then solve for x by multiplying the entire inequality by 2.
The answer is 15and not the others
An interesting question! Let's take a look at the rectangular prism first.
[Rectangular Prism]
We know that the formula for the volume of a rectangular prism is:
volume = length * width * height
or more simply
V = L*W*H
All we know is that the volume is 210 cubic meters. We can choose whatever we want for the dimensions to force it to work! We're free to do what we want!
210 = L*W*H
I like 10, that's a nice number. Let's make L = 10.
210 = 10*W*H
Hmm... but now I need W*H to be 21 (think about it, make sure you get why I say that). Well, how about W = 7 and H = 3? That should work.
210 = 10*7*3
It checks! Possible dimensions for the rectangular prism are L = 10 meters, W = 7 meters, and H = 3 meters. There are many other choices of course, but this is a possible choice.
[Triangular Prism]
Same idea, different formula. For a triangular prism, the volume is
V = 1/2 * L*W*H
But the volume is still 210 cubic meters, so we just have
210 = 1/2 * L*W*H
So, one of our dimensions is going to be cut in half. Why don't we just double L to make up for it?
210 = 1/2*(20)*W*H
And we can leave W and H the same
210 = 1/2*20*7*3
Check that it works! A possible choice is L = 20 meters, W = 7 meters and H = 3 meters.
We're done!
There's no such thing as parallel or perpendicular "to a point". A problem like that
will always want the new line to be parallel or perpendicular to another <em><u>line</u></em>.
-- If the new line is parallel to the given line, then they have the <em><u>same</u></em> slope.
-- If the new line is perpendicular to the the given line, then the slope of the
new line is [ <em><u>1 / slope of the given line</u></em> ].
In either case, you now have the slope of the new line and a point on it.
From there, you should have no trouble finding its equation.