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3 years ago

Use estimation to check the answer to this story problem.

Mathematics

2 answers:

aniked [119]3 years ago

4 0

C.The answer should be about 8,000 yards. The student's answer is not correct. because 765*11=8415

Lelechka [254]3 years ago

3 0

Here, the answer would be: 765 * 11 = 8415 [ About 8 thousands ]

In short, Your Answer would be Option C) The answer should be about 8,000 yards. The student's answer is not correct.

Hope this helps!

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True or False: A trapezoid is a polygon that has two bases, each with a different length.

elixir [45]

……….Yes it is true that trapezoid is a polygon that has two bases

8 0

2 years ago

Read 2 more answers

A shipment of 105 Otter box covers for I-phones has arrived. The total invoice (excluding tax, shipping, etc.) is $3,849.75.

bezimeni [28]

3,849.75 ÷ 49.95 = 77 (Calculator)

Sense you would like it explained than the question is asking how many otter box Defender Covers where shipped in that price. So when you have that they want the amount of Otter Box Defenders than you divide the amount paid for the shipment with the amount of the otter box defender price.

I hope this is helpful.

3 0

3 years ago

in 2001, the population in a town was 12% more than it was in 2000. if the population was 25,160 in 2002, which is 10% more than

blagie [28]

2002=25,160
2001=22,644
2000=19,926.72 (need to round to 19,926)
2001:
25,160/10=2516
25,160-2516

2000:
22,644/10=2,264.4 (10%)
2,264.4/5=452.88 (2%)
2,264.4+452.88=2717.28 (12%)
22,644-2717.28=19.926.72

3 0

3 years ago

I need help with this ASAP and can you explain so i can understand?!

Elanso [62]

Answer:

Adult tickets sold = 225

Student Tickets sold = 375

Step-by-step explanation:

Let:

Adult tickets sold = x

Student Tickets sold = y

Total tickets sold = 600

So, we can write: x+y = 600

Total money collected = 3037.50

Cost of 1 Adult ticket = $6.00

Cost of one Student ticket = $4.50

So, we can write: 6x+4.5y=3037.50

Now, we get a system of equations, that if solved we can find values of x and y

Let:

$x+y = 600--eq(1)\\6x+4.5y=3037.50--eq(2)$

We can solve using substitution method.

Finding value of x from eq(1) and putting it in eq(2)

$We\:have\\x+y=600\\x=600-y$

Put in eq(2)

$6x+4.5y=3037.50\\6(600-y)+4.5y=3037.50\\3600-6y+4.5y=3037.50\\-1.5y=3037.50-3600\\-1.5y=-562.5\\y=\frac{-562.5}{-1.5}\\y=375$

So, we get value of y = 375

Now put value of y in eq(1) to find value of x

$x+y=600\\Put\:y=375\\x+375=600\\x=600-375\\x=225$

So, we get value of x = 225

The Tickets sold will be:

Adult tickets sold = x = 225

Student Tickets sold = y = 375

3 0

2 years ago

Read 2 more answers

Find a and b if the point p(6,0) and Q(3,2) lie on the graph of ax+ by=12

tiny-mole [99]

to get the equation of any straight line we only need two points off of it, hmmm let's use P and Q here and then let's set the equation in standard form, that is

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

$(\stackrel{x_1}{6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{6}}}\implies \cfrac{2}{-3}\implies -\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{2}{3}}(x-\stackrel{x_1}{6})$

$\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{3}}{3(y-0)~~ = ~~3\left( -\cfrac{2}{3}(x-6) \right)}\implies 3y=-2(x-6) \\\\\\ 3y=-2x+12 \implies \stackrel{a}{2} x+\stackrel{b}{3} y=12$

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2 years ago