Answer:
The correct option is the graph on the bottom right whose screen grab is attached (please find)
Step-by-step explanation:
The information given are;
The required model height for the designed clothes should be less than or equal to 5 feet 10 inches
The equation for the variance in height is of the straight line form;
y = m·x + c
Where x is the height in inches
Given that the maximum height allowable is 70 inches, when x = 0 we have;
y = m·0 + c = 70
Therefore, c = 70
Also when the variance = 0 the maximum height should be 70 which gives the x and y-intercepts as 70 and 70 respectively such that m = 1
The equation becomes;
y ≤ x + 70
Also when x > 70, we have y ≤ -x + 70 with a slope of -1
To graph an inequality, we shade the area of interest which in this case of ≤ is on the lower side of the solid line and the graph that can be used to determine the possible variance levels that would result in an acceptable height is the bottom right inequality graph.
Answer:
x=10
y=-2
(10,-2)
Step-by-step explanation:
If X=10, we can put 10 in for x in the equation.
30 + 5y = 20
Next, we need to solve to find y.
We will get y on its own so we subtract 30 from 20 to get
5y=-10
We then know that 5 goes into -10 -2 times.
y=-2
Answer: 3.61×10^5 A
Step-by-step explanation: Since the brain has been modeled as a current carrying loop, we use the formulae for the magnetic field on a current carrying loop to get the current on the hemisphere of the brain.
The formulae is given below as
B = u×Ia²/2(x²+a²)^3/2
Where B = strength of magnetic field on the axis of a circular loop = 4.15T
u = permeability of free space = 1.256×10^-6 mkg/s²A²
I = current on loop =?
a = radius of loop.
Radius of loop is gotten as shown... Radius = diameter /2, but diameter = 65mm hence radius = 32.5mm = 32.5×10^-3 m = 3.25×10^-2m
x = distance of the sensor away from center of loop = 2.10 cm = 0.021m
By substituting the parameters into the formulae, we have that
4.15 = 1.256×10^-6 × I × (3.25×10^-2)²/2{(0.021²) + (3.25×10^-2)²}^3/2
4.15 = 13.2665 × 10^-10 × I/ 2( 0.00149725)^3/2
4.15 = 1.32665 ×10^-9 × I / 2( 0.000058)
4.15 × 2( 0.000058) = 1.32665 ×10^-9 × I
I = 4.15 × 2( 0.000058)/ 1.32665 ×10^-9
I = 4.80×10^-4 / 1.32665 ×10^-9
I = 3.61×10^5 A