IT IS SO FIRST YOU WANNA GO TO THIS LINK IT WILL SHOW YOU EVERY THING HERE IT IS DEz.........................................................................NUTS
1/2 divided by 1/6 is 3
use KCF strategy
1/2 x 6/1=3
1x6=6
2x1=2
6/2=3
Answer:
4.47
Step-by-step explanation:
a^2+b^2=c^2
2^2+4^2=c^2
4+16=c^2
20=C^2
= 
4.47=c
Your statemtent is incomplete.
I found the samestatment with the complete words: <span>Simplify
completely quantity x squared minus 3 x minus 54 over quantity x
squared minus 18 x plus 81 times quantity x squared plus 12 x plus </span>36 over x plus 6
Given that your goal is to learn an be able to solve any similar problem, I can teach you assuming that what I found is exactly what you need.
x^2 - 3x - 54 x^2 + 12x + 36
------------------ x ---------------------
x^2 - 18x + 81 x + 6
factor x^2 - 3x - 54 => (x - 9)(x + 6)
factor x^2 - 18x + 81 => (x - 9)^2
factor x^2 + 12x + 36 = (x + 6)^2
Now replace the polynomials with the factors=>
(x - 9) (x + 6) (x + 6)^2 (x + 6)^2 x^2 + 12x + 36
------------------------------ = --------------- = --------------------
(x - 9)^2 (x + 6) (x - 9) x - 9
Answer:
<em>0 $20 bills and 10 $5 bills</em>
<em>1 $20 bills and 6 $5 bills</em>
<em>2 $20 bills and 2 $5 bills</em>
Step-by-step explanation:
<u>Equations</u>
Let's set:
x=number of $5 bills
y=number of $20 bills
The total amount Sara has is given by
5x+20y
And we know it's equal to $50, thus:
5x+20y=50
Dividing by 5
x+4y=10
We would need another condition to solve for x and y, but we can determine some combinations that solve the problem.
Solving for x:
x=10-4y
Since both x and y are integers and cannot be negative:
10-4y≥0
Swapping sides:
4y≤10
Dividing by 4:
y≤2.5
Thus, y can only have the values {0,1,2}
For y=0
x=10-4*0=10
x=10
For y=1
x=10-4*1=6
x=6
For y=2
x=10-4*2=2
x=2
Thus, the possible combinations are:
0 $20 bills and 10 $5 bills
1 $20 bills and 6 $5 bills
2 $20 bills and 2 $5 bills
