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babymother [125]
2 years ago
12

A and B start toward each other at the same time from points 150 miles apart.

Mathematics
1 answer:
Inessa [10]2 years ago
8 0

Answer:

B must travel at the rate of 10 miles per hour.

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Can someone please solve number 2 ! I would literally love you forever !!!!
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Answer:

sorry i wish i knew how but i would like to give you aomething other than an answer for your question and i hope this is ok.

Step-by-step explanation:

every day is a new day and a new opportunity to change the world no matter how BIG or how small.  even if you make mistakes. always remember this though. whatever you put into the world, whether it be good or bad, it will always come back three times.

meaning that when you do something good something three times as good will happen to you. The same is so for bad except it would be 3 times as bad as will happen to you.   I hope your day is great and may you do many great things.

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How many solutions does this equation have?
zhenek [66]
One solution because when you switch the - to the other side it will be positive which will equal one and make it one solution.
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7 0
3 years ago
Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

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3 years ago
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