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tester [92]
3 years ago
10

HURRYYYY::::: Which of the following functions is graphed above? OA f(x) = 4 * log (x + 4) OB . f(x) = 4 * log (x + 4) OC f(x) =

4 * log (- x - 4) OD f(x) = 4 * log (x + 4)

Mathematics
1 answer:
almond37 [142]3 years ago
3 0

In order for the curve to move upwards from left to right as shown the log and x values need to be negatives. The curved line crosses the x axis to the right of the origin, so there needs to be a positive value added to x.

The answer is d. F(x) = -4log(-x+4)

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Solve the equation for y in terms of x<br><br> 3x-2y=6
Katarina [22]

Answer: 3/2x - 3 = y

Step-by-step explanation:

3x - 2y = 6

   +2y  =     +2y

3x = 6 + 2y

-6   = -6

3x-6 = 2y

/2     = /2

3/2X - 6/2 = y

3/2x - 3 = y

6 0
3 years ago
Eric is saving $60 every week to buy a new laptop that costs $480. He has already saved $180.
Rama09 [41]

Answer:

Step-by-step explanation:

You saved $200 on a laptop you purchased online. If this was a 25% savings from the original price, find the original cost of the laptop.

13,962 results

Math

You saved $200 on a laptop you purchased online. If this was a 25% savings from the original price, find the original cost of the laptop.

7 0
3 years ago
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Please help me with this Geometry question
Lelu [443]

Answer:

Given that JN was bisected, JL ≅ LN

Given that KM was bisected, KL ≅ ML

∠JLK ≅ ∠MLN because of vertical angles.

∠JLK is contained by JL and KL.

∠MLN is contained by ML and LN.

Therefore ΔJKL ≅ ΔNML by the SAS postulate.

Step-by-step explanation:

The SAS postulate states that when you know two triangles have an equal angle, and that angle is formed by two sides that are equal in both triangles, the two triangles are congruent.

When a line is bisected, it means it was cut in two equal parts.

Since two lines were bisected and each form a side in the triangles, two sides are congruent.

The contained angles, ∠JLK and ∠MLN, are equal because of vertical angles. Vertical angles occur when two straight lines intersect. Angles that are opposite to each other are equal in all cases.

7 0
3 years ago
Match the information on the left with the appropriate equation on the right.
kiruha [24]

Answer:

See attachment below

Step-by-step explanation:

For the first option, we are given m = - 2 / 3, b = 3. This is likely in the point - slope form y = mx + b, where m = slope and b = y - intercept. Thus, the equation of the line in point - slope form given this information, should be y = - 2 / 3x + 3. It seems as if none of the following equations match this form, so let us interchange the equation a bit,

y = - 2 / 3x + 3,

y + 2 / 3x = 3,

2x + 3y = 9 - Option C

_______________________________________________________

Next we are given m = - 3 / 2, and that this line passes through the point ( 4, - 1 ). Substitute m as - 3 / 2, x as 4, y as - 1, knowing point ( 4, - 1 ), into the form y = mx + b - solving for b.

- 1 = ( - 3 / 2 )( 4 ) + b,

b = 5,

Thus the equation in point - slope form should be y = - 3 / 2x + 5. None of the choices match this, so let us again alter the equation,

y = - 3 / 2x + 5,

2y = - 3x + 10,

- 2y = 3x - 10 - Option A

_______________________________________________________

( 6, 3 ) and ( 3, 1 ) is given to lie on this line. The slope of the line should be as follows,

Slope = 3 - 1 / 6 - 3 = 2 / 3

Now let us determine the y - intercept ( b ) by substitute one of the points, say ( 6, 3 ). In this case x = 6, and y = 3,

3 = ( 2 / 3 )( 6 ) + b,

b = - 1,

y = 2 / 3x - 1 = Option D

Take a look at the attachment below for further help;

3 0
3 years ago
Which congruence theorems can be used to prove △EFG ≅ △JHG? Check all that apply.
sasho [114]

Answer:

ASA  and AAS

Step-by-step explanation:

We do not know if these are right triangles; therefore we cannot use HL to prove congruence.

We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.

We are given that EF is parallel to HJ.  This makes EJ a transversal.  This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent.  We also know that ∠EGF and ∠HGJ are vertical angles and are congruent.  This gives us two angles and a non-included side, which is the AAS congruence theorem.

Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent.  Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.

4 0
3 years ago
Read 2 more answers
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