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Serga [27]
3 years ago
6

Please help! how many imaginary roots?

Mathematics
1 answer:
olga55 [171]3 years ago
3 0
Yes what the person above me said
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ROUND 258,177 TO THE NEAREST HUNDRED THOUSAND
Galina-37 [17]

258,177 to the NEAREST HUNDRED THOUSAND is 258,000 and nothing else...

If this number was 275,550, the NEAREST HUNDRED THOUSAND would've been 276,000 because of the last three digits in this number...

7 0
3 years ago
Y = x^2+ 2x + 7<br> y = 7 + x
Lostsunrise [7]

Answer:

when x=0 y=7

when x=-1 y= 6

Step-by-step explanation:

to find x & y we can make the two x expressions equal to each other

x²+2x+7=7+x (we are going to set it equal to zero to find the roots/the x value)

x²+x=0

x(x+1)=0

x=0 x=-1 (two solutions for x)

now we just plug in these values and find the y values

when x=0 y=7

when x=-1 y= 6

5 0
3 years ago
Find cos θ given that cos 2θ = 5/6 and 0 ≤ θ &lt; π/2. Give an exact answer
trasher [3.6K]
\bf \textit{Double Angle Identities}&#10;\\ \quad \\&#10;sin(2\theta)=2sin(\theta)cos(\theta)&#10;\\ \quad \\&#10;cos(2\theta)=&#10;\begin{cases}&#10;cos^2(\theta)-sin^2(\theta)\\&#10;1-2sin^2(\theta)\\&#10;\boxed{2cos^2(\theta)-1}&#10;\end{cases}&#10;\\ \quad \\&#10;tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\\\\&#10;-------------------------------\\\\&#10;

\bf cos(2\theta)=\cfrac{5}{6}\implies 2cos^2(\theta)-1=\cfrac{5}{6}\implies 2cos^2(\theta)=\cfrac{5}{6}+1&#10;\\\\\\&#10;2cos^2(\theta)=\cfrac{11}{6}\implies cos^2(\theta)=\cfrac{11}{12}\implies cos(\theta)=\pm\sqrt{\cfrac{11}{12}}


now, bear in mind, the square root gives us +/- versions, so, which is it? well, we know the angle is in the range of "<span>0 ≤ θ < π/2", that simply means the 1st quadrant, so, we'll use the positive one then

</span>\bf cos(\theta)=\cfrac{\sqrt{11}}{\sqrt{12}}\implies cos(\theta)=\cfrac{\sqrt{11}}{2\sqrt{3}}&#10;\\\\\\&#10;\textit{now, let's rationalize the denominator}&#10;\\\\\\&#10;\cfrac{\sqrt{11}}{2\sqrt{3}}\cdot \cfrac{\sqrt{3}}{\sqrt{3}}\implies \cfrac{\sqrt{11}\cdot \sqrt{3}}{2\sqrt{3^2}}\implies \cfrac{\sqrt{11\cdot 33}}{2\cdot 3}\implies \boxed{\cfrac{\sqrt{33}}{6}}<span>
</span>
3 0
4 years ago
False<br> True<br> or<br> 3.<br> Circle:<br> 2'-<br> 2'
jekas [21]

Answer:

true

Step-by-step explanation:

8 0
3 years ago
Help please thank you so much
siniylev [52]

Answer:

14

Step-by-step explanation:

If you count the dots (excluding 3 because it says more than three hours) you get 14.

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