Answer:
Step-by-step explanation:
System 1 has no solution, and System 2 has infinitely many solutions. Wait, YOUR IN HIGH SCHOOL?! IM IN 8TH GRADE AND IM DOING THIS??!! well, idk how to solve this, but these are the answers.
Answer:
Both are similar by SAS similarity.
This SAS similarity is equivalent to the congruence.
Step-by-step explanation:
Step 1:
To prove that ACB and HIG as similar triangles.
We have to look upon the corresponding sides.
SAS= Side angle sides , there the angle must be in between two sides.
ACB = HIG
Lets work on the corresponding sides.
IG/AC = IH/AC
=
Reducing each to lowest form, we divide numerator and denominator by 3 for the 1st fraction and by 4 for the 2nd fraction.
We have
=
Both sides are equal.
So its proved that both are similar with SAS similarity theorem.
Answer:
Step-by-step explanation:
a= adult ticket
a= student ticket
5a+1s=2874
1a+1s=1246
Subtract the second equation from the first one
4a=1628
a=407
a+s=1246
407+s=1246
s=839
Answer: The starting time is 2:27 and finishing time is 7:09.
Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.
Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.
That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes, so the time taken to cover 1 street is 3 minutes.
Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.
And his finishing time was (4:30 + 3×53 min) = 7:09.
Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as
Thus, the starting and finishing time was 2:27 and 7:09 respectively.
He payed 0.72
First you take 2.88, then you multiply it by 1/4 or a simpler way would be to divide 2.88 by 4. The answer is $0.72