To calculate the velocity, we use the given expression above which is <span>s(t) = −16t^2 + 144. First, we calculate the time it takes to reach the ground. Then, differentiate the expression and substitute time to the differentiated expression.
</span>s(t) = −16t^2 + 144
0 = -16t^2 + 144
t = 3
s'(t) = v = -32t
v = -32(3)
v = -96
Note: negative sign signifies that the object is going down
T: 8x+19
7x-2(4-2x)+6(5-x)-x+2-(6x+5) = 7x-8+2x+30+6x-x+2-6x-5 = 8x+19
Y: 56-8x
9-(-2-3x)+4(-x+6)-x+12-3(2x-3) = 9+2+3x-4x+24-x+12-6x+9 = 56-8x
Answer:
(x+4)(3x^2 + 2)
Step-by-step explanation:
3x^3+12x^2+2x+8
3x^2(x + 4) + 2(x + 4)
(x+4)(3x^2 + 2)
Answer:
(6, 2)
Step-by-step explanation:
K is at (-2, -3)
<u>Using the transformation equation given for this problem:</u>
(x + 8, y + 5)
(-2 + 8, -3 + 5)
(6, 2)
The answer is the third option.
Answer:
Step-by-step explanation:
y - y₁ = m ( x - x₁)
y - 5 = - 3 (x - 12)
y - 5 = -3x + 36
3x + y = 36 + 5
3x + y = 41
y = -3x + 41
