What are extremes in math with an example so I can understand it better?

The population of Adamsville grew from 7,000 to 12,000 in 5 years. Assuming uninhibited exponential growth, what is the expected

mr Goodwill [35]

We have that if we assume standard exponential growth, the equation of the population will be: $7000*e^{kt}$ if we start counting from the moment that the population was 7000. We are given that 7000* $e^{5k}$ =12000, namely that P(5)=12000 and we need to find $7000e^{(5+5)k}=7000e^{10k}$ . Since e^(10k)=e^(5k)*e^(5k), and since we can solve for e^(5k) from P(5), we have:
e^(5k)=12000/7000 and we can calculate P(10). P(10)=7000 $\frac{12000^2}{7000^2}$ = 20571 people.

3 0

3 years ago

Joseph and Wendy were catching tadpoles. At first Wendy caught nine times three more than Joseph caught. Joseph was upset and re

Dmitriy789 [7]

Answer:

Joseph caught 7 tadpoles

Step-by-step explanation:

Let the number of tadpoles caught by Joseph be x

The number of tadpoles Wendy caught will be ;

9(x + 3)

After Joseph was upset, he released half of Wendy’s tadpole and then six times as many as Joseph caught swam away leaving Wendy with only three tadpoles left;

Hence, mathematically;

9(x + 3)/2 - 6x = 3

Multiply through be 2

9(x + 3) - 12x = 6

9x + 27 -12x = 6

9x -12x = 6-27

3x = 21

x = 21/3

x = 7

6 0

3 years ago

In science class, the students observed 24 of the 300 frogs from the local aquarium. If 6 of the frogs observed had spots, how m

Alona [7]

Answer:

225 frogs

Step-by-step explanation:

Total population of frogs = 300 frogs.

Observed population of frogs = 24

6 of the 24 observed frogs had spots

Which means , the number of frogs that did not have spots = 24 - 6 = 18 frogs.

We were told to find how many of the total population can be predicted to NOT have spots. We would form a proportion.

If 24 frogs = 18 frogs with no spots

300 frogs = Y

Cross multiply

24Y = 300 × 18

Y = (300 × 18) ÷ 24

Y = 5400 ÷ 24

Y = 225 frogs.

This means out of 300 frogs, 225 frogs do not have spots.

Therefore, the total population that can be predicted to NOT have spots is 225 frogs.

the total population can be predicted to NOT have spots

3 0

2 years ago

When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probabili

svlad2 [7]

Critical probability is the essentially cut-off value. The critical probability when the confidence level of 58% is 0.79.

<h3>What is the critical probability?</h3>

Critical probability is the essentially cut-off value that defines the region where the test statistic is unlikely to lie.

As it is given that the confidence level is 58%. therefore, in order to calculate the critical probability, we need to calculate the margin of error within a set of data, and it is given by the formula

$\rm Critical\ Probability, (P*) = 1-\dfrac{\alpha }{2}$