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3 years ago

What are extremes in math with an example so I can understand it better?

Mathematics

1 answer:

anzhelika [568]3 years ago

3 0

Y=x2 the extreme would be x=0

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PLS Help! What is the best approximation for the perimeter of a semicircle with a diameter of 12cm? Use 3.14 to approximation pi

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Answer:

Step-by-step explanation:

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3 years ago

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A survey of

Zina [86]

Answer:

0.0208<p<0.0592

Step-by-step explanation:

-Given the sample size is 400 and the desired proportion is 16.

-The confidence interval can be determined as follows:

$CI=\hat p\pm z\sqrt{\frac{\hat p(1-\hat p}{n}}\\\\\hat p=x/n=16/400=0.04$

#We the use this proportion to find the CI at 95%:

$CI=0.04\pm 1.96\times \sqrt{\frac{0.04(1-0.04)}{400}}\\\\=0.04\pm 0.0192\\\\=[0.0208,0.0592]$

Hence, the 95% confidence interval is 0.0208<p<0.0592

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3 years ago

I need help.<br><br> someone help please!

Vikentia [17]

Sorry, I think there is missing context?

4 0

3 years ago

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Point M is the midpoint of AB. The coordinates of point A are (-8, 3) and the coordinates of M are (-2, 1). What are the coordin

ch4aika [34]

Answer:

the coordinates of point B are (-5, 2)

Step-by-step explanation:

1. use midpoint formula to find the midpoint (equation attached below)

2. plug in the numbers

$(\frac{-8+(-2)}{2},\frac{3+1}{2})$

3. solve

$(\frac{-8-2)}{2},\frac{3+1}{2})$

$(\frac{-10}{2},\frac{4}{2})$

$(-5,2})$

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3 years ago

LAST ATTEMPT! MARKING AS BRAINLIEST!! ( simplifying radicals)

klasskru [66]

$\huge \bf༆ Answer ༄$

Let's solve ~

$\qquad \looparrowright \sf - 2 \sqrt{192 {k}^{4} }$

$\qquad \looparrowright \sf - 2 \sqrt{2 {}^{6} \times 3{k}^{4} }$

$\qquad \looparrowright \sf - 2 \times 2 {}^{3} \times {k}^{2} \times \sqrt{3}$

$\qquad \looparrowright \sf - 16 {k}^{2} \sqrt{3}$

Hence, the correct choice is D

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2 years ago

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