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Verdich [7]
3 years ago
8

Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to StartFraction 1 Over 4 EndFraction of

itself the result is a 15. The modern day equation that models this problem is x plus StartFraction 1 over 4 EndFraction x equals 15.. What is the solution to the equation? x = 10 x = 12 x = 15 x = 30 What is the fee Michael charges each new subscriber?
Mathematics
1 answer:
Rzqust [24]3 years ago
6 0

Answer:

x=12

Step-by-step explanation:

For the given situation , a quantity x is added to \frac{1}{4} x gives 15.

We can set up equation as

x+\frac{1}{4}x=15

Multiply each term by 4 on both sides to get rid the denominator.

It gives,

4 x+x=60

Now, combine like terms

5 x=60

Divide both sides by 5

x=12.

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3 years ago
I need the answer fore both plsss
grandymaker [24]

Answer:  6i) 6a² - 2ab

               6ii) -2b³

               6iii) b³ + 7b² - 49b

<u>Step-by-step explanation:</u>

6i)   (a + b)(5a - 3b)             +    (a - 3b)(a - b)

=    5a² - 3ab + 5ab - 3b²   +    a² - ab - 3ab + 3b²

=    5a² + 2ab - 3b²             +   a² - 4ab + 3b²

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6ii)    (a - b)(a² + b² + ab)              -  (a + b)(a² + b² - ab)

=   a³ + ab² + a²b - ab² - a²b - b³ -  (a³ + ab² - a²b -ab² + a²b + b³)

=   a³ - b³                                      -  (a³ + b³)

=   a³ - b³                                      - a³ - b³

= -2b³

6iii) (b² - 49)(b + 7)             +     343

=     b³ + 7b² - 49b - 343    +    343

=     b³ + 7b² - 49b

You are allowed a maximum of 3 questions.

Please post #7 on a different question.

5 0
3 years ago
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