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____ [38]
3 years ago
8

a biker must circle a 12 mile track twice. His average speed must be 60mph. On his first lap he averaged 50 mph. How fast must h

e travel on his second lap to qualify?
Mathematics
1 answer:
liq [111]3 years ago
8 0

Answer:

75 mph

Step-by-step explanation:

A biker must circle a 12-mile track twice. His average speed must be 60 mph.

So, the average time required to cover the distance is \frac{2 \times 12}{60} = 0.4 hours.

Now, on his first lap, he averaged 50 mph.

So, he covered this 12 miles track in \frac{12}{50} = 0.24 hours.

Hence, he has to cover the next 12 miles track in (0.4 - 0.24) = 0.16 hours.

Therefore, his average speed in the second round must be \frac{12}{0.16} = 75 mph to qualify. (Answer)

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a) <em>Slope of the line m = ∞</em>

<em>b) Slope of the line  m =0</em>

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<u><em>Step(i):-</em></u>

<em>Given points are ( 7,7) and (7,-8)</em>

<em>Slope of the line</em>

<em>                      </em>m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }<em />

<em>                     </em>m = \frac{-8-7 }{7-7  } = \frac{-15}{0} = infinite<em />

<em>                   m = ∞</em>

<u><em>Step(ii):-</em></u>

Given points are (-6,7) and (9,7)

<em>Slope of the line</em>

<em>                      </em>m = \frac{y_{2} - y_{1} }{x_{2}-x_{1}  }<em />

<em>                     </em>m = \frac{7-7  }{9-(-6)  } = \frac{0}{15} = 0<em />

<em>Slope of the line  m =0</em>

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