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STALIN [3.7K]
3 years ago
6

some microbiologists recommend inoculating a pair of OF basal media (without carbohydrate) along with the carbohydrate media. Wh

y do you think this is done
Biology
2 answers:
lutik1710 [3]3 years ago
8 0

Answer:

This is to ensure accurate recording and  interpretations of the observed results without Carbohydrate.

To ensure that the observed results was due to the expected investigating factor, and not due to any external factor.

Explanation:

The basal media without  carbohydrate is the negative control setup. since there is no carbohydrate their will be no  bacterial growth .Therefore the activities of the bacteria can be fully observed . However the basal media with carbohydrate  have full growth since CHO is available as nutrient; ,asexual reproduction will occur and growth takes palce.  Thus the control(without CHO) and the  actual experiment can be compared for accuracy. Therefore the basal media without CHO. acted as active negative control for results analysis and interpretation.

In addition the two growth media  should be   inoculated. Thus any observable changes can be attributed to bacterial growth, and not due to any external factors.This justify  reasons for the answers above.

Taya2010 [7]3 years ago
5 0

Answer:

As a control, which, in this case, is a negative control. Since there is no carbohydrate added there will be no bacterial growth. In your tubes which do have some carbohydrate there will be bacterial growth. Since you used a control you can compare any changes in the tubes in which you have growth to the tubes without growth, which would represent the original state of the media. This makes any results easier to notice and interpret rather than having to remember what the tubes used to look like.

It also ensures that any change in the media is due to the growth of the bacteria and not some external factor. Since both sets of tubes were inoculated but only one set shows some change you can be sure that that change is due to the growth of the bacteria.

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Answer:

Explanation:

1.During glycolysis,four molecules of ATP are formed,and two are expended to cause the initial phosphorylation of glucose to get the process going.This gives a net gain of two molecules of ATP

For every glucose molecule that undergoes cellular respiration, the citric acid cycle is carried out twice; this is because glycolysis (the first stage of aerobic respiration) produces two pyruvate molecules per glucose molecule. During pyruvate oxidation (the second stage of aerobic respiration), each pyruvate molecule is converted into one molecule of acetyl-CoA—the input into the citric acid cycle. Therefore, for every glucose molecule, two acetyl-CoA molecules are produced. Each of the two acetyl-CoA molecules goes once through the citric acid cycle.

The citric acid cycle begins with the fusion of acetyl-CoA and oxaloacetate to form citric acid. For each acetyl-CoA molecule, the products of the citric acid cycle are two carbon dioxide molecules, three NADH molecules, one FADH2 molecule, and one GTP/ATP molecule. Therefore, for every glucose molecule (which generates two acetyl-CoA molecules), the citric acid cycle yields four carbon dioxide molecules, six NADH molecules, two FADH2 molecules, and two GTP/ATP molecules. The citric acid cycle also regenerates oxaloacetate, the molecule that starts the cycle.

While the ATP yield of the citric acid cycle is modest, the generation of coenzymes NADH and FADH2 is critical for ATP production in the final stage of cellular respiration, oxidative phosphorylation. These coenzymes act as electron carriers and donate their electrons to the electron transport chain, ultimately driving the production of most of the ATP produced by cellular respiration.

3 0
3 years ago
How do ecologists define an ecosystem?
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3 years ago
If 1/8 remains after 21 years, what is the half-life?
vagabundo [1.1K]

Half life formula

The number of unstable nuclei remaining after time t can be determined according to this equation:

N(t) = N(0) * 0.5^(t/T)

where:

N(t) is the remaining quantity of a substance after time t has elapsed.

N(0) is the initial quantity of this substance.

T is the half-life.

It is also possible to determine the remaining quantity of a substance using a few other parameters:

N(t) = N(0) * e^(-t/τ)

N(t) = N(0) * e^(-λt)

τ is the mean lifetime - the average amount of time a nucleus remains intact.

λ is the decay constant (rate of decay).

All three of the parameters characterizing a substance's radioactivity are related in the following way:

T = ln(2)/λ = ln(2)*τ

How to calculate the half life

Determine the initial amount of a substance. For example, N(0) = 2.5 kg.

Determine the final amount of a substance - for instance, N(t) = 2.1 kg.

Measure how long it took for that amount of material to decay. In our experiment, we observed that it took 5 minutes.

Input these values into our half life calculator. It will compute a result for you instantaneously - in this case, the half life is equal to 19.88 minutes.

If you are not certain that our calculator returned the correct result, you can always check it using the half life formula.

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