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8_murik_8 [283]
3 years ago
13

On discovering that her family had a 70% risk of heart attack, Erin took a treadmill test to check her own potential of having a

heart attack. The doctors told her that the reliability of the stress test is 67%. What is the probability that Erin will not have a heart attack and the test predicts that she will?

Mathematics
1 answer:
Rashid [163]3 years ago
5 0

<u>Answer-</u>

The probability that Erin will not have a heart attack and the test predicts that she will is, 46.5% .

<u>Hint-</u> This a conditional probability problem where Bayes theorem should be applied.

<u>Solution-</u>

Applying Bayes theorem,

P(No\ heart\ attack\ |\ Correctly\ tested)

=\frac{P(Correctly\ tested\ |\ No\ heart\ attack)P(No\ heart\ attack)}{P(Correctly\ tested)}

P(Correctly\ tested\ |\ No\ heart\ attack)=67\%=0.67

P(No\ heart\ attack)=1-P(heart\ attack)=1-0.7=0.3

P(Correctly\ tested)=[P(No\ heart\ attack)\times P(Correctly\ tested)]+[P(Heart\ attack)\times (Incorrectly\ tested)]

=[0.3\times 0.67]+[0.7\times 0.33]=0.432

Putting the values,

P(No\ heart\ attack\ |\ Correctly\ tested)=\frac{0.67\times 0.3}{0.432} =0.465

∴ There is a 46.5% chance that Erin will not have a heart attack even though the test predicts that she will.

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2) Eliminate parentheses:

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<em>Comments on the solutions</em>

The expression we add in each case eliminates the constant on one side of the equation and the variable term on the other side. That leaves an equation of the form ...

  variable term = constant

We choose to eliminate the smaller variable term (the one with the coefficient farthest to the left on the number line). Then the constant we eliminate is the on on the other side of the equation. This choice ensures that the remaining variable term has a positive coefficient, tending to reduce errors.

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