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ch4aika [34]
3 years ago
9

Determine the equation for the given line in

Mathematics
2 answers:
Tema [17]3 years ago
6 0

Answer:

Y= -3/5 - 1

Step-by-step explanation:

if you start on the y intercept an go down once (-1)

then go down three times (-3)

positive 5 so go right 5 times it lands on the point :)

im not a teacher and i took this last year so sorry if my explanation isn't the best

Maksim231197 [3]3 years ago
5 0
Ok so the answer is at the top why are u down her
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What is the rate of change of the linear relationship modeled in the table? (4 points) x y −2 5 −1 4 0 3 1 2 a −2 b −1 c negativ
Ostrovityanka [42]

Answer:

rate of change=slope= y2-y1/x2-x1

Step-by-step explanation:

x: -2|-1|0|1

y : 5|4|3|2

so choose 2 ordered pairs. in this case, we will choose (-2,5) and (-1,4)

now we plug them in: \frac{4-5}{-1-(-2)}

4-5=-1

-1-(-2)=1

so -1/1 is equal to -1, meaning it's answer option b.

4 0
3 years ago
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Which of the following best describes the equation below?
ivann1987 [24]

Answer:

B.

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Step-by-step explanation:

2(x + 11) + 5x = 7x - 22

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7x +22 = 7x-22

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4 0
4 years ago
Civil engineer wants to estimate the maximum number of cars that can safely travel on a particular road at a given speed. He ass
pychu [463]
N(s)= \frac{89s}{14+14( \frac{s}{17})^2 }
\\
\\N'(s)= (\frac{89s}{14+14( \frac{s}{17})^2 } )'= \frac{89\times 14(1+( \frac{s}{17})^2)-89s\times  \frac{28}{17} }{14^2(1+( \frac{s}{17})^2)} 
\\
\\N'(s)=0
\\
\\89\times 14(1+( \frac{s}{17})^2)-89s\times  \frac{28}{17}=0
\\
\\1+( \frac{s}{17})^2- \frac{2s}{17} =0
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\\289+s^2-34s=0
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\\s^2-34s+289=0
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\\s=17

5 0
3 years ago
Can someone check on this problem if I did it right this problem is about law of cosines just look at #1
lora16 [44]

Answer:

x = 5.57

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x² = 10² + 6² − 2(10)(6) cos 29°

x = 5.57

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8 0
4 years ago
Can anyone answer me this question ​
yuradex [85]

Question 1:

For this case we have the following functions:

f (x) = 4x + 1\\g (x) = x ^ 3 + 1

We must findg_ {o} f (0):

By definition we have to:

g_ {o} f = g (f (x))\\f_ {o} g = f (g (x))

g (f (x)) = (4x + 1) ^ 3 + 1

We substitute x = 0:

g (f (0)) = (4 (0) +1) ^ 3 + 1 = 1 ^ 3 + 1 = 2

So, we have that g (f (0)) = 2

Answer:

g (f (0)) = 2

Question 2:

For this case we have the following functions:

f (x) = 4x + 1\\g (x) = x ^ 3 + 1

We must find f_ {o} g (0):

By definition we have to:

f_ {o} g = f (g (x))\\f (g (x)) = 4 (x ^ 3 + 1) + 1 = 4x ^ 3 + 4 + 1 = 4x ^ 3 + 5

We substitute x = 0:

f (g (0)) = 4 (0) ^ 3 + 5 = 5

Answer:

f (g (0)) = 5

Question 3:

For this case we must find the inverse of the following function:

h (x) = \frac {2x + 1} {3}

To do this, we follow the steps below:

We change y for h (x):

y = \frac {2x + 1} {3}

We exchange variables:

x = \frac {2y + 1} {3}

We clear the value of the variable "y":

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We change y for h^{ -1} (x):

h ^{ - 1} (x) = \frac {3x} {2} - \frac {1} {2}

Answer:

h ^ {- 1} (x) = \frac {3x} {2} - \frac {1} {2}

3 0
4 years ago
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