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ZanzabumX [31]
3 years ago
12

How can one become a world scientist?

Computers and Technology
2 answers:
Lynna [10]3 years ago
8 0
No need to woory abt age !!! In today's competitive grant world, this phenomenon is exacerbated. It is dangerous to one's funding to go against the trend, and if there is a lab to support and mouths to feed, the disincentives are great. This phenomenon stifles creativity, perhaps far more than biological age does. 
<span>While it is not frequently acknowledged either in the popular press or in scientific literature, a significant fraction of scientific discovery is the result of serendipity (or to put it more bluntly, luck). From the discovery of penicillin by Fleming to the discovery of new ionization techniques such as MALDI that power modern mass-spectrometry based proteomic research, luck has frequently played a big role. Such discoveries are generally attributed to hard work and genius, rather than to luck. Doing so gives the “genius” too much credit and luck too little.
</span><span>Risk taking is where most of the big discoveries in science lie. so takerisks.
</span>enjoy  always specially when you r  working and learn to say no
Learning to say “no” is particularly important for young faculty, who find themselves barraged with such requests, and who can easily get sucked into full-time committee duties. It is wise to step back frequently and ask, “overall, is this work I am doing fun?” If the answer is no, perhaps it is time to revisit and consider diving into a new area.
<span>Note the distinction in this guideline from: “learn to write and present well.”
</span><span>Understanding and conveying the big picture for one's work is perhaps the greatest challenge facing young scientists
</span>That's all I can give.
larisa [96]3 years ago
4 0
Make sure they like science enough to be a world scientist
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3 years ago
write a java program that prompts the user to enter scores (each number an integer from 0 to 10) and prints the following output
Vladimir [108]

Answer:

Explanation:

The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int count = 0;

       int highest, lowest;

       ArrayList<Integer> myArr = new ArrayList<>();

       while (true) {

           System.out.println("Enter a number [0-10] or -1 to exit");

           int num = in.nextInt();

           if (num != -1) {

               if ((num >= 0) && (num <= 10)) {

                   count+= 1;

                   myArr.add(num);

               } else {

                   System.out.println("Wrong Value");

               }

           } else {

               break;

           }

       }

       if (myArr.size() > 3) {

           highest = myArr.get(0);

           lowest = myArr.get(0);

           for (int x: myArr) {

               if (x > highest) {

                   highest = x;

               }

               if (x < lowest) {

                   lowest = x;

               }

           }

           System.out.println("Number of Elements: " + count);

           System.out.println("Highest: " + highest);

           System.out.println("Lowest : " + lowest);

       } else {

           System.out.println("Number of Elements: " + count);

           System.out.println("No Highest or Lowest Elements");

       }

   }

}

4 0
3 years ago
The development methodology where each part of a project is done in order after each other is called:
Oksanka [162]

Bruh this a duplicate

8 0
3 years ago
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laiz [17]

Answer:

def analyze_text(sentence):

   count = 0

   e_count = 0

   for s in sentence:

       s = s.lower()

       if s.isalpha():

           count += 1

       if s == "e":

           e_count += 1

   return "The text contains " + str(count) + " alphabetic characters, of which " + str(e_count) + " (" + str(e_count*100/count) + "%) are ‘e’."

Explanation:

Create a function called analyze_text takes a string, sentence

Initialize the count and e_count variables as 0

Create a for loop that iterates through the sentence

Inside the loop, convert all letters to lowercase using lower() function. Check each character. If a character is a letter, increment the count by 1. If a character is "e", increment the e_count by 1.

Return the count and e_count in required format

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Answer:

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Explanation:

6 0
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