3 years ago

SolveCos75 degree -cos15 degree=-1÷√12

Mathematics

1 answer:

anygoal [31]3 years ago

7 0

Answer:

Step-by-step explan122

ation:

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$\bf tan(68^o)=\cfrac{\stackrel{opposite}{1.5}}{\stackrel{adjacent}{x}}\implies x=\cfrac{1.5}{tan(68^o)}\implies x\approx 0.61 \\\\[-0.35em] ~\dotfill\\\\ tan(56^o)=\cfrac{\stackrel{opposite}{1.5}}{\stackrel{adjacent}{w}}\implies w=\cfrac{1.5}{tan(56^o)}\implies w\approx 1.01 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{\textit{width of the crater}}{x+w\implies 1.62}~\hfill$

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3 years ago

SolveCos75 degree -cos15 degree=-1÷√12​

SolveCos75 degree -cos15 degree=-1÷√12