I don’t know dawg sorry g
Answer:
A= I think because it is definite not c so there is a solution differently I know so that is my final answer.
Sorry if I am wrong.
Take the sqrt of both sides of <span>(x+2)^2=10:
x+2 = plus or minus sqrt(10)
Solve for x: x = -2 plus or minus sqrt(10)
Evaluate x: x = -2 + sqrt(10) AND x = -2 - sqrt(10) (answers)
</span>
X - 18 = 35. 53 is x, since 53 - 18 = 35.
The longest possible altitude of the third altitude (if it is a positive integer) is 83.
According to statement
Let h is the length of third altitude
Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.
From Area of triangle
A = 1/2*B*H
Substitute the values in it
A = 1/2*a*12
a = 2A / 12 -(1)
Then
A = 1/2*b*14
b = 2A / 14 -(2)
Then
A = 1/2*c*h
c = 2A / h -(3)
Now, we will use the triangle inequalities:
2A/12 < 2A/14 + 2A/h
Solve it and get
h<84
2A/14 < 2A/12 + 2A/h
Solve it and get
h > -84
2A/h < 2A/12 + 2A/14
Solve it and get
h > 6.46
From all the three inequalities we get:
6.46<h<84
So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.
Learn more about TRIANGLE here brainly.com/question/2217700
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