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3 years ago

Veronica randomly surveyed a group of students to find out how they arrived at school that

Mathematics

1 answer:

Finger [1]3 years ago

8 0

Answer:A

Step-by-step explanation:

-Long way

1.) Add all the numbers of people together (60)

2.) Divide all the students aka.540 by 60. (9)

3.) Multiply 9 by all the numbers.

=Answer for all. (Double check)

-Mental math

1.) look at chart

2.) compare 8 and 7

3.) figure out which is larger.

=Answer of A

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3 years ago

What is the median of the ages shown in this stem-and-leaf plot? 59.5 58.5 59.0 58.0 Stem and leaf plot titled Ages of college p

AlexFokin [52]

Answer:

Median = 59.0

Step-by-step explanation:

According to the given data:

The data represents the signatures collected by different volunteers are as following in order from least to the greatest:

30, 32, 41, 44, 44, 45, 53, 55, 58, 59, 62, 62, 62, 65, 66, 68, 75, 75, 76

And it is required to find the median:

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So, the median will be at the place number 10

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3 years ago

Read 2 more answers

Solve triangle ABC if AB=24.6, BC=29.7, and CA=30

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Triangle ABC equals 84.3

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3 years ago

A construction crew is lengthening a road. The road started with a length of 59 miles, and the crew is adding 2 miles to the roa

Illusion [34]

The answer is L = 59 + 2(d). If we plug in our numbers, we will get L = 59 + 2(32). 2*32 is 64, and if you add 59 you get 123 miles.

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2 years ago

What is the perimeter of this quadrilateral? (5,5) (2, 4) (4, 1) (6, 1)

lbvjy [14]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}$

$BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}$

$DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89$

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2 years ago