18. If f(x)=[xsin πx] {where [x] denotes greatest integer function}, then f(x) is:
since x denotes the greatest integers which could the negative or the positive values, also x has a domain of all real numbers, and has no discontinuous point, then x is continuous in (-1,0).
Answer: B]
20. Given that g(x)=1/(x^2+x-1) and f(x)=1/(x-3), then to evaluate the discontinuous point in g(f(x)) we consider the denominator of g(x) and f(x). g(x) has no discontinuous point while f(x) is continuous at all points but x=3. Hence we shall say that g(f(x)) will also be discontinuous at x=3. Hence the answer is:
C] 3
21. Given that f(x)=[tan² x] where [.] is greatest integer function, from this we can see that tan x is continuous at all points apart from the point 180x+90, where x=0,1,2,3....
This implies that since some points are not continuous, then the limit does not exist.
Answer is:
A]
Answer:
56.43
Step-by-step explanation:
52.25 + 4.18 (8% tax)
Well you could do 5(60x+20y), 100(3x+y), and 2(150x+50y)
Answer:
a= 78
Step-by-step explanation:
To solve subtract:
180-102= 78
Hope this helps!
Answer:
12xy
Step-by-step explanation:
Product of [x y] [1 2] is
(xy)×(12)=12xy
