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OLEGan [10]
3 years ago
5

Solve for x. X + 0.60(15) = 0.80(x + 15)

Mathematics
2 answers:
devlian [24]3 years ago
8 0

Answer: D 15

Step-by-step explanation:

galben [10]3 years ago
4 0

x+0.60(15)=0.80(x+15)\ \ \ \ |\text{use distributive property}\\\\x+9=0.80x+12\ \ \ \ |-9\\\\x=0.8x+3\ \ \ \ |-0.8x\\\\0.2x=3\ \ \ \ |\cdot5\\\\\boxed{x=15}

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Ray Of Light [21]

I let the computer do the graphing.  

f(x) = x(x + 3)²(1 - x) / 3

We see obvious zeros at x=0, x=-3 and x=1.

f(x) = x(x + 3)²(1 - x) / 3

f(x) = x(x^2 + 6x + 9)(1 - x)/3

f(x) = x(x^2 + 6x + 9 - x^3 - 6x^2 - 9x)/3

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f(x) = (-x^4 - 5x^3 -3x^2 +9x)/3

f'(x) = (-4x^3 - 15x^2 -6x + 9)/3

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f'(x) = (x + 3) (-4x^2 - 3x + 3)

We get stationary points when x = -3 or

x = (-1/8)( 3 ± √(9 - 4(-4)(3))) =  (-3 ± √57)/8  about -1.3 and 0.6 which are a local minimum and maximum respectively.

f''(x) = (-12x^2 - 30x -6)/3 = -4x^2 - 10x - 2

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Concave up, positive, a CUP

(-3 - √57)/8, f((-3 - √57)/8) ) is a minimum.

f''((-3 + √57)/8) = -4(.6)^2 - 10(.6) - 2 = -9.44

CDN, ( ((-3 + √57)/8), f((-3 + √57)/8) ) is a maximum.

I didn't evaluate f((-3 ±√57)/8) which are around -3 and 1 but I leave that calculation to you.

6 0
3 years ago
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3 years ago
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Answer:

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Step-by-step explanation:

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5 0
4 years ago
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