Join the centre O to the chord (let it be MN) & let OH be the perpendicular to the chord
OH bisects MN into 2 equal parts (each one is x/2)
OMH is a right triangle with one side =8, the second leg =x/2 & the hypotenuse = 12 (Radius)
Apply Pythagoras:
12² = 8² +(x/2)² ==>144=64 + x²/4 ==> x²=4(144-64) =320
x²=320==> x=√320 =17.88 ≈17.9
Answer:
12 boys
Step-by-step explanation:
I believe the answer is 12 boys. I hope this helps!
Answer:
an infinite number of solutions
Step-by-step explanation:
−3x −17 = −17 −3x
left side = right side TRUE because -3x-17 is the same as -17-3x
we can rearrange the the equation
−3x −17 +17 = −17 +17−3x, add 17 on both sides of the equations
-3x = -3x, divide both sides by (-3)
x = x
Since this equation is <u>always true ( for any number ) </u>we have <u>an infinite number of solutions</u> (since there are is an infinity of numbers.)
Step-by-step explanation:
<em>Let </em><em>the </em><em>two </em><em>numbers </em><em>be </em><em>x </em><em>and </em><em>y </em>
<em>x </em><em>-</em><em> </em><em>y </em><em>=</em><em> </em><em>6</em><em>8</em><em>5</em>
<em>Let </em><em>the </em><em>smaller </em><em>number </em><em>be </em><em>y </em>
<em>x </em><em>-</em><em> </em><em>2</em><em>6</em><em>2</em><em> </em><em>=</em><em> </em><em>6</em><em>8</em><em>5</em>
<em>x </em><em>=</em><em> </em><em>6</em><em>8</em><em>5</em><em> </em><em>+</em><em> </em><em>2</em><em>6</em><em>2</em>
<em>Therefore </em><em>x </em><em>=</em><em> </em><em>9</em><em>4</em><em>7</em>
