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3 years ago

Here are the first four terms of an arithmetic sequence.

Mathematics

2 answers:

ololo11 [35]3 years ago

5 0

Answer:

nth term = 7n - 2

Step-by-step explanation:

a = first term = 5

d = common difference = second term - first term

= 12 - 5 =7

d = 7

$a_{n} =$ a + (n-1)d

= 5 + (n -1)7

= 5 + 7n - 7 {add like terms}

= 7n - 2

SashulF [63]3 years ago

3 0

Answer:

n_n = n_n-1 + 7

Step-by-step explanation:

All it does is it adds 7 to the previous term

n = n_(previous)+7

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Take up to the third-order derivative:

$f(x)=(-3x+15)^{3/2}$

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$f(2)=9^{3/2}=27$

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Then the Taylor polynomial is

$P_3(x)=f(2)+f'(2)(x-2)+\dfrac{f''(2)}2(x-2)^2+\dfrac{f'''(2)}6(x-2)^3$

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Answer:

Step-by-step explanation:

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