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Aneli [31]
3 years ago
7

The line graph shows a direct variation with a unit rate of 1.4. Two of the points the line passes through are (5, 7) and (10, 1

4).
What is the slope of the line?

Mathematics
2 answers:
cupoosta [38]3 years ago
6 0

Answer: slope = 7/5

Step-by-step explanation:

The line graph is a straight line graph. Two of the points the line passes through are (5, 7) and (10, 14).

The slope, m of the graph is expressed as

m = slope = (change in the value of y in the y axis) / (change in the value of x in the x axis).

Slope = (y2 - y1)/(x2 - x1)

y2 represents final value of y = 14

y1 represents initial value of y = 7

x2 represents final value of x = 10

x1 represents initial value of x = 5

Therefore,

Slope = (14 - 7)/(10 - 5) = 7/5

vlada-n [284]3 years ago
4 0

Answer:

slope of the line is m=\frac{7}{5}

Step-by-step explanation:

<u>Step 1:-</u>

The slope of the given line

\frac{y_{2-Y_{1} } }{x_{2} -x_{1} }

<u>step 2:-</u>

m = frac{7}{5}[/tex]

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ad-work [718]

Answer:

28

Step-by-step explanation:

In this question, the units are just the number of boxes/grid-squares. So count how many boxes they have to walk between each step. You start at the top left location, and go around to all of them counting the boxes they pass.

they should all add up to 28 boxes, or 28 units!

3 0
2 years ago
Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds a
kirill115 [55]

Answer:

12 feet per second.

Step-by-step explanation:

Please consider the complete question.

Ian tosses a bone up in the air for his dog, Spot. The height, h, in feet, that Spot is above the ground at the time t seconds after she jumps for the bone can be representedh(t)=-16t^2+20t.

What is Spot's average rate of ascent, in feet per second, from the time she jumps into the air to the time she catches the bone at t=1/2?  

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

\text{Average rate of change}=\frac{h(\frac{1}{2})-h(0)}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot(\frac{1}{2})^2+20\cdot \frac{1}{2}-(-16\cdot(0)^2+20\cdot (0))}{\frac{1}{2}-0}

\text{Average rate of change}=\frac{-16\cdot\frac{1}{4}+10-(0)}{\frac{1}{2}}

\text{Average rate of change}=\frac{-4+10}{\frac{1}{2}}

\text{Average rate of change}=\frac{6}{\frac{1}{2}}

\text{Average rate of change}=\frac{2\cdot 6}{1}

\text{Average rate of change}=12

Therefore, Spot's average rate of ascent is 12 feet per second.

3 0
3 years ago
P=f/a, where f=70 and a=20 f is increased by 10 a is increased to by 10 <br><br>​
valina [46]

Answer:

P=3.5

P=2.667

Step-by-step explanation:

p=f/a

P=70/20

P=3.5

then f is increased by 10

f=70+10=80

and a is increased by 10

a=20+10

a=30

therefore; P=f/a

P=80/30

P=2.667

3 0
2 years ago
Which is the best way to write (8/x) as a verbal expression?
Elanso [62]

Answer:

None of these.

Step-by-step explanation:

8/x is the result when 8 is divided by x.

4 0
3 years ago
A racquetball club charges $10 for a one-month trial membership. After the trail month, the regular membership fee is $12 per mo
Furkat [3]
Membership is discounted $2 for first month
c=cost of one month
d=discount=$2
x=# of months
xc - 2= total cost
x for 1 month is 1, c is always 12, -2 is constant
1 x(12) - 2=10 for first month
8 months
8c -2=total cost for 8 months
8 x 12 - 2= 94 for 8 months

5 0
3 years ago
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