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pshichka [43]
3 years ago
14

A certain business school has 500 students, and the law school at the same university has 800 students. Among these students, th

ere are 30 sibling pairs consisting of 1 business student and 1 law student. If 1 student is selected at random from each school, what is the probability that a sibling pair is selected?
Mathematics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

<em>3/40000</em>

Step-by-step explanation:

<em>Data:</em>

<em>Business 500 students</em>

<em>Laws 800 students</em>

<em>30 pairs of siblings, 1 in each school</em>

<em />

<em>It is required to calculate the probability that a random pair of siblings is chosen.</em>

<em />

<em>For this:</em>

<em>Business, of 500 students we have 30 siblings to choose one</em>

<em />

<em>30/500</em>

<em />

<em>Continue, choose the sibling's partner, Laws, of 800 only 1 is the sibling of the chosen in Business.</em>

<em />

<em>1/800</em>

<em />

<em>So we have:</em>

<em>(30/500) * (1/800) = 30/400000 = 3/40000</em>

<em />

<em>You can choose in reverse, first Laws and then Business, leaving:</em>

<em>(30/800) * (1/500)= 30/400000 = 3/40000</em>

<em />

<em>And it gives the same result: 3/40000</em>

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<h3>What is Equation?</h3>

An equation is a mathematical expression that contains an equals symbol. Equations often contain algebra. Algebra is used in math when you do not know the exact number in a calculation.

Given that:

Pules Rs 4000 per night but will decrease the amount by R100 per person occupying the chalet.

Number of People          Cost per night

          1                                       4000

          2                                       3900

          3                                      3800

          4                                       3700

          5                                       3600

          6                                       3500

          7                                       3400

          8                                       3300

          9                                       3200

          10                                      3100

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equation:   C=  4000-100(n-1)

      for n=1: C= 4000- 0=4000

            n=2, C= 4000-100(1)= 3900

The graph is attached below:

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