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boyakko [2]
3 years ago
6

What does the square root of 200 simplify to?

Mathematics
1 answer:
tatiyna3 years ago
5 0
√200 - √32 (find the largest perfect square factors of 200 and 32, which are 100 and 16 respectively) √(100*2) - √(16*2) (take the square root of 100 and 16) 10√2 - 4√2 (subtract) 6√2 <===ANSWER
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Write 2x+3y=6 in slope intercept form
Leokris [45]
Slope-intercept form:
y=mx+b

m=slope
b=y-intercept

2x+3y=6
3y=-2x+6
y=-2/3 x+6/3
y=-2/3 x+2

Answer: the line in slope-intercept form would be:
y=-2/3 x+2
3 0
3 years ago
A clothing design company pays two different people to design its T-shirts.
irina [24]

Answer: D

Step-by-step explanation:

5 0
3 years ago
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Which of the following trigonometric inequalities has no solution over the interval 0 ≤ x ≤ 2pi radians?
valentinak56 [21]

Answer:

A .cos(x)<1

Step-by-step explanation:

According to the first inequality

cos(x)<1

x < arccos 1

x<0

This therefore does not have a solution within the range 0 ≤ x ≤ 2pi

x cannot be leas than 0. According to the range not value, 0≤x which is equivalent to x≥0. Thus means otvis either x = 0 or x> 0.

For the second option

.cos(x/2)<1

x/2< arccos1

x/2<0

x<0

This inequality also has solution within the range 0 ≤ x ≤ 2pi since 0 falls within the range of values.

For the inequality csc(x)<1

1/sin(x) < 1

1< sin(x)

sinx>1

x>arcsin1

x>90°

x>π/2

This inequality also has solution within the range 0 ≤ x ≤ 2pi since π/2 falls within the range of values

For the inequality csc(x/2)<1

1/sin(x/2) < 1

1< sin(x/2)

sin(x/2)> 1

x/2 > arcsin1

X/2 > 90°

x>180°

x>π

This value of x also has a solution within the range.

Therefore option A is the only inequality that does not have a solution with the range.

6 0
4 years ago
Anthony borrowed $18,800 at 6% simple interest for 4 months. Determine the amount of interest.
anygoal [31]
First, converting R percent to r a decimal
r = R/100 = 6%/100 = 0.06 per year,
putting time into years for simplicity,
4 months ÷ 12 months/year = 0.333333 years,
then, solving our equation

I = $ 376.00

I = 18800 × 0.06 × 0.333333 = 375.999624
I = $ 376.00

The simple interest accumulated
on a principal of $ 18,800.00
at a rate of 6% per year
for 0.333333 years (4 months) is $ 376.00.
5 0
3 years ago
Which number in the monomial 125x^18y^3z^25 needs to be changed to make it a perfect cube
Oksana_A [137]

Hi,

You just have to change z^25 to z^24 or z^27.

125x^{18}y^3z^{24}=(5x^6*y*z^8)^3

4 0
3 years ago
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