Check the picture below.
so the shape is really 4 triangles with a base of 2 and a height of 4 each, and 2 squares tha are 4x4.
![\bf \stackrel{\textit{area of the 4 triangles}}{4\left[\cfrac{1}{2}(2)(4) \right]}~~+~~\stackrel{\textit{area of the two squares}}{2(4\cdot 4)}\implies 16+32\implies 48](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%204%20triangles%7D%7D%7B4%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%282%29%284%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20two%20squares%7D%7D%7B2%284%5Ccdot%204%29%7D%5Cimplies%2016%2B32%5Cimplies%2048)
Step-by-step explanation:
the intersection of the interval: (-∞, 7) and [-5, +∞)
is [-5, 7)
and the union of the interval: (-∞, 7) and [-5, +∞)
is (-oo, +oo)
You gotta show a picture buddy, good luck
you repair it with a tuba glue!
Answer:
? = 7/2
Step-by-step explanation:
? = x
a denominator can’t be equal to 0
x ≠ 0
14/x = 4
14 = 4x
x = 7/2