Answer:
1.) n-10
2.) 4 / x=x (dont trust me on this)
3.) -8n+1
4.) 1/2 - 19 ( dont trust me on this)
5.)3/5-21 or 3/5>21
6.)x^+15
Step-by-step explanation:
I tried double check it
its been awhile
Answer:
4
Step-by-step explanation:
<h3><u>some relevant limit laws</u></h3>
lim C = C where c is a constant.
lim( f(x) + g(x)) =lim f(x) + lim g(x)
lim( f(x)g(x)) =lim f(x) * lim g(x)
lim( cg(x)) =clim g(x)
lim( f(x)/g(x)) =lim f(x) / lim g(x) if lim g(x) is not equal to zero.
lim( f(x))^2 = (lim f(x) )^2
lim square root( f(x)) = square root(lim f(x) )
![\lim_{n \to 3} g(x) = 9\\\\\lim_{n \to 3} f(x) = 6\\\\ \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10} \\\\ = \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10}\\\\= \sqrt[3]{lim_{n \to 3}f(x) \times lim_{n \to 3}g(x) + 10}\\\\= \sqrt[3]{6 \times 9 + 10}\\\\= \sqrt[3]{64}](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%203%7D%20g%28x%29%20%20%3D%209%5C%5C%5C%5C%5Clim_%7Bn%20%5Cto%203%7D%20f%28x%29%20%20%3D%206%5C%5C%5C%5C%20%5Clim_%7Bn%20%5Cto%203%7D%20%5Csqrt%5B3%5D%7Bf%28x%29g%28x%29%20%2B%2010%7D%20%5C%5C%5C%5C%20%3D%20%5Clim_%7Bn%20%5Cto%203%7D%20%5Csqrt%5B3%5D%7Bf%28x%29g%28x%29%20%2B%2010%7D%5C%5C%5C%5C%3D%20%5Csqrt%5B3%5D%7Blim_%7Bn%20%5Cto%203%7Df%28x%29%20%5Ctimes%20lim_%7Bn%20%5Cto%203%7Dg%28x%29%20%2B%2010%7D%5C%5C%5C%5C%3D%20%5Csqrt%5B3%5D%7B6%20%5Ctimes%209%20%2B%2010%7D%5C%5C%5C%5C%3D%20%5Csqrt%5B3%5D%7B64%7D)
= 4
Answer:
Step-by-step explanation:
"Factors" are the numbers you multiply to get another number. For instance, factors of 15 are 3 and 5, because 3×5 = 15. Some numbers have more than one factorization (more than one way of being factored). For instance, 12 can be factored as 1×12, 2×6, or 3×4.
Answer:
y = 15
Step-by-step explanation:
The triangles follow a scale factor. This scale factor can enlarge or make a triangle smaller, using this factor, like a ratio. We can do 22/10 to get this scale factor for the set, which is 2.2. Finally, divide 33 by 2.2 to get 15 for the missing side length y.
Answer:

Step-by-step explanation:

When dividing two exponents (of the same bases) you subtract the exponents. When there is an exponent to an exponent, you multiply the to exponents.