Which of the following is the correct factored form of the given equation?

Mathematics

1 answer:

svetoff [14.1K]3 years ago

3 0

Answer: 3

Step-by-step explanation:

You might be interested in

How many possibilities are there when you toss a coin and draw a card from a standard deck of cards? A.54 B.72 C.112 D.104

kaheart [24]

I think D would be the correct answer

8 0

3 years ago

Read 2 more answers

A 1.8 ounce jar of cinnamon costs $4.05.what is the cost per ounce?

Mademuasel [1]

If a 1.8 ounce jar costs $4.05, you want to do $4.05 divided by 1.8. That will give you the cost per ounce.

$4.05 / 1.8 = $2.25 per ounce.

4 0

4 years ago

Read 2 more answers

If triangle dgh is congruent to triangle def find the value of x

Rom4ik [11]

Answer:

x = 25

Step-by-step explanation:

$\triangle DGH\sim\triangle DEF... (given)$

$\frac{DG}{DE} =\frac{GH}{EF}$

$\frac{52}{91} =\frac{x+3}{2x-1}$

$\frac{4}{7} =\frac{x+3}{2x-1}$

4(2x - 1) = 7(x + 3)

8x - 4 = 7x + 21

8x - 7x = 21 + 4

x = 25

8 0

3 years ago

How many 3-digit even numbers are that begin with either 5 or 6?

mojhsa [17]

Answer: 100 3 digit even number that begin with either 5 or 6

Explanation:
Case 1:
A 3 digit that begin with 5 should be 500-599 so there are 100 numbers
But we are only finding even number
So 100/2 = 50 3-digit even number that begin with 5.

Case 2:
A 3 digit that begin 6 should have
600-699 and there are also 100 number including even and odd in total. Since we are only finding even number we get:
100/2 = 50 3-digit even number that begin with 6.

Plus both case together we get 50 3-digit even number that begin with 5 + 50 3-digit even number that begin with 6= 50 + 50 = 100

8 0

4 years ago

Read 2 more answers

You enter a chess tournament where your probability of winning a game is 0.3 against half the players (call them type 1), 0.4 ag

Doss [256]

The probability of winning is 0.44 .

Step-by-step explanation:

Here it's given that , You enter a chess tournament where your probability of winning a game is 0.3 against half the players (call them type 1), 0.4 against a quarter of the players (call them type 2), and 0.5 against the remaining quarter of the players (call them type 3). You play a game against a randomly chosen opponent. More precisely :

$Probability(type1) = 0.3\\Probability(type2) = 0.4\\Probability(type3) = 0.5\\\\Probability(winning) = w$