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Naddika [18.5K]
3 years ago
10

Vince has a rectangular rug in his room with an area of 10 ft the length of the rug is 18 inches longer than the width what coul

d be the dimensions of the rug?
Mathematics
1 answer:
aev [14]3 years ago
4 0

The length of the rug is 4 ft.

The width of the rug is 2.5 ft.

Explanation:

The area of the rug is 10 ft.

The length of the rug be l.

Let us convert the inches to feet.

Thus, 18 inches =  1.5 ft

Thus, the length of the rug is l=1.5+w

Let the width of the rug be w.

Substituting these values in the formula of area of the rectangle, we get,

A=length\times width

10=(1.5+w)(w)\\10=1.5w+w^2\\w^2+1.5w-10=0

Solving the expression using the quadratic formula,

$w=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Substituting the values, we have,

$w=\frac{-15 \pm \sqrt{15^{2}-4 \cdot 10(-100)}}{2 \cdot 10}\\

$w=\frac{-15 \pm \sqrt{4225}}{20}$

$w=\frac{-15 \pm 65}{2 0}$

Thus,

w=\frac{-15 + 65}{2 0}\\w=\frac{50}{20} \\w=2.5  and   w=\frac{-15 - 65}{2 0}\\w=\frac{-80}{20} \\w=-4

Since, the value of w cannot be negative, the value of w is 2.5ft

Thus, the width of the rug is 2.5ft

Substituting w=2.5 in l=1.5+w, we get,

l=1.5+2.5\\l=4

Thus, the length of the rug is 4 ft.

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