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Daniel [21]
3 years ago
6

Is the product 1.01 1.01 less than or greater than 1?

Mathematics
1 answer:
faust18 [17]3 years ago
8 0

Answer:

greater than 1

Step-by-step explanation:

its greater because 1.01 is greater than 1

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Pada hari kantin sebanyak 800 naskah kupon telah dijual,harga senaskah kupon masing masing rm 30 dan rm 50 .jumlah wang diperole
solniwko [45]

Answer:

Step-by-step explanation:

On the day of the canteen, 800 coupons were sold, the price of each coupon was RM 30 and RM 50 respectively. The amount of money earned from the sale of coupons was RM30000. How many copies of RM30 and RM50 coupons were sold?

Let:

RM 30 = x

RM 50 = y

x + y = 800 - - - (1)

30x + 50y = 30000 - - - (2)

From (1)

x = 800 - y

Put x = 800 - y in (2)

30(800 - y) + 50y = 30000

24000 - 30y + 50y = 30000

24000 + 20y = 30000

20y = 30000 - 24000

20y = 6000

y =

4 0
3 years ago
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
3 years ago
Write an equivalent expression for the expression shown below:<br><br> a/3 + a/3 + a/3
iris [78.8K]

Answer:

3 (a/3) = a

Step-by-step explanation:

a/3 + a/3 + a/3

3 times a/3

the 3's cancel each other out

A

Keep up the good work! =)

3 0
3 years ago
What is the counter example for 'if you do not eat beef then you're not vegetarian'
slamgirl [31]

Answer: If you're not vegetarian, then you do not eat beef.

Step-by-step explanation:

Dismiss the 'if' and 'then':

- you do not eat beef

- you're not vegetarian

Now, all you have to do is switch their places:

- you're not vegetarian

- you do not eat beef

Now add the 'if' and 'then' back:

If you're not vegetarian, then you do not eat beef.

4 0
3 years ago
Determine the lateral area and surface area of the given prism. Round answers to the nearest whole number.
vazorg [7]

Answer:

Lateral Area = Area of 2 triangle + Area of slant rectangle + area of back rectangle

Lateral Area = (5m)(3m) + (6m) (36m) + (3m) (36m)

LA = 15m² + 216m² + 108m²

LA = 339 m²

SA = (5m)(3m) + (6m) (36m) + (3m) (36m) + (5m)(36m)

SA = 15m² + 216m² + 108m² + 180 m²

SA = 519 m²

3 0
2 years ago
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