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Rom4ik [11]
3 years ago
11

Janessa can run 1/2 of a mile in 4 1/3 minutes what is her unit rate in miles per minute ​

Mathematics
1 answer:
Anna007 [38]3 years ago
4 0

Answer:

8 2/3 minutes in 1 mile

Step-by-step explanation:

1/2 = 4 1/3

1 = 8 2/3

HOPE THIS HELPS

PLZZ MARK BRAINLIEST

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When factored completely, <br> X^3-7x^2-30x
sweet-ann [11.9K]

Answer:

x(x+3)(x−10)

Step-by-step explanation:

Hope this was helpful let me know if it was!

5 0
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Concerns about the climate change and CO2 reduction have initiated the commercial production of blends of biodiesel (e.g. from r
natta225 [31]

Answer:

a) 99% of the sample means will fall between 0.933 and 0.941.

b) By the Central Limit Theorem, approximately normal, with mean 0.937 and standard deviation 0.0015.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

(a) If the true mean is 0.9370 with a standard deviation of 0.0090 within what interval will 99% of the sample means fail?

Samples of 34 means that n = 34

We have that \mu = 0.937, \sigma = 0.009

By the Central Limit Theorem, s = \frac{0.009}{\sqrt{34}} = 0.0015

Within what interval will 99% of the sample means fail?

Between the (100-99)/2 = 0.5th percentile and the (100+99)/2 = 99.5th percentile.

0.5th percentile:

X when Z has a pvalue of 0.005. So X when Z = -2.575.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-2.575 = \frac{X - 0.937}{0.0015}

X - 0.937 = -2.575*0.0015

X = 0.933

99.5th percentile:

X when Z has a pvalue of 0.995. So X when Z = 2.575.

Z = \frac{X - \mu}{s}

2.575 = \frac{X - 0.937}{0.0015}

X - 0.937 = 2.575*0.0015

X = 0.941

99% of the sample means will fall between 0.933 and 0.941.

(b) If the true mean 0.9370 with a standard deviation of 0.0090, what is the sampling distribution of ¯X?

By the Central Limit Theorem, approximately normal, with mean 0.937 and standard deviation 0.0015.

6 0
3 years ago
HELP ASAP 15 POINTS!!!<br> What is the solution to this equation?<br> 6(x-5)=4x+20
Andre45 [30]

Answer:

<h2><u><em>x = 25</em></u></h2>

Step-by-step explanation:

What is the solution to this equation?

6 * (x - 5) = 4x + 20

6x - 30 = 4x + 20

2x = 20 + 30

2x = 50

x = 50 : 2

x = 25

-------------------

check

6 * ( 25 - 5) = 4 * 25 + 20

6 * 20 = 100 + 20

120 = 120

the answer is good

3 0
2 years ago
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Round 0.01123 to the nearest hundredth?
Rasek [7]
The answer to your question would be 0.01
7 0
3 years ago
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I need help with this rq
Vesnalui [34]

Answer:

228.4

Step-by-step explanation:

9.2 + 9.2 + 60 + 75 +75 which is 228.4. Remember to divide the triangles by two after you do base times height.

7 0
2 years ago
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