Answer:
This is a simple slope intercept form equation: y=ax+b
Where a is the slope and b is the y-intercept, but in this problem the y-intercept is 0 so it is no shown.
The line on the graph would be negative (downward) because of the negative and would be going down by a slope of -5.
-down 5 over 1 ( rise over run )
We start by finding the intercept of the line: what does y equal when x=0? and what does x equal when y=0?
• intercept in x
y = 12 + 2x
0 = 12 + 2x
-12 = 2x
-6 = x
• intercept in y
y = 12 + 2x
y = 12 + 2(0)
y = 12 + 0
y = 12
Now we find three more points giving y a value and finding x
y = 12 + 2x
2 = 12 + 2x
2-12 = 2x
-10 = 2x
-5 = x
y = 12 + 2x
6 = 12 + 2x
6 - 12 = 2x
-6 = 2x
-3 = x
y = 12 + 2x
14 = 12 + 2x
14 - 12 = 2x
2 = 2x
1 = x
Notice how I gave y even numbers as values since we would have to divide with 2 at the end.
Sol. {(-6,0)(0,12)(-5,2)(-3,6)(1,14)}
(- 5, - 6 )
for x- coordinate x + 5 = 0 ⇒ x = - 5
given f(x) ± c , the value of c translates the graph vertically up/down by ± c
here c = - 6 , thus graph is shifted down by - 6
thus the vertex = (- 5, - 6)
Answer:
12 is the answer thanks for asking in
