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3 years ago

-8x+114=11x+10-11x what's the answer

Mathematics

1 answer:

gtnhenbr [62]3 years ago

4 0

The answer is x=13

I hope this helps!
Ask me for the work!

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What is the pythagorean theorem

Molodets [167]

C in square=A in square+B in square

6 0

3 years ago

Read 2 more answers

Gary drove to the park at a rate of 50 miles per hour if it took him 2.5 hours to get from his house to the park how far away is

Marina86 [1]

Answer:

The distance of the park from the Gary's house is 125 miles.

Step-by-step explanation:

Speed of Gary = 50 miles/hour

Time taken by Gary to reach the park from his house = 2.5 hours

Now, we know that,

Distance travelled = speed × time

So, distance between park and Gary's house = speed × time

= 50 × 2.5

= 125 miles

So, the park is 125 miles away from the Gary's house.

4 0

3 years ago

What is the difference of 15 and 7?<br> O<br> 3<br> Sondrit<br> Not

viva [34]

Answer:

Step-by-step explanation:

6 0

2 years ago

The perimeter of a triangle is 140 cm the length of the second side is twice the length of the first side the length of the thir

kykrilka [37]

Perimeter = 140

Side 1 = x

Side 2 = 2x

Side 3 = 3x - 10

x + 2x + 3x - 10 = 140

6x - 10 = 140

6x = 150

x = 25

Side 1 = 25 cm

Side 2 = 50 cm

Side 3 = 65 cm

Hope this helps!! :)

6 0

2 years ago

Read 2 more answers

The equation h(t) = -16t² + 80t + 64 represented the height, in feet, of a potato t seconds after it has been launched.

Lyrx [107]

Answer:

Part A) The potato hit the ground at t=5.70 seconds (see the explanation)

Part B) The potato is 40 feet off the ground at the time t=5.28 seconds (see the explanation)

Step-by-step explanation:

we have

$h(t)=-16t^2+80t+64$

where

h(t) is the height of a potato in feet

t is the time in seconds

Part A) Write an equation that can be solved to find when the potato hits the ground. Then solve the equation

we know that

When the potato hit the ground, the value of h(t) must be equal to zero

For h(t)=0

$-16t^2+80t+64=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+80t+64=0$

$a=-16\\b=80\\c=64$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(64)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{10,496}} {-32}$

$t=\frac{-80+\sqrt{10,496}} {-32}=-0.70$

$t=\frac{-80-\sqrt{10,496}} {-32}=5.70$

therefore

The potato hit the ground at t=5.70 seconds

Part B) Write an equation that can be solved to find when the potato is 40 feet off the ground. Then solve the equation

For h(t)=40 ft

substitute in the quadratic equation

$-16t^2+80t+64=40$

$-16t^2+80t+24=0$

Solve the quadratic equation

we have

$a=-16\\b=80\\c=24$

substitute in the formula

$t=\frac{-80\pm\sqrt{80^{2}-4(-16)(24)}} {2(-16)}$

$t=\frac{-80\pm\sqrt{7,936}} {-32}$

$t=\frac{-80+\sqrt{7,936}} {-32}=-0.28$

$t=\frac{-80-\sqrt{7,936}} {-32}=5.28$

therefore

The potato is 40 feet off the ground at the time t=5.28 seconds

3 0

3 years ago