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Schach [20]
3 years ago
9

Left Wic loves her pet frogs. If she spends $4.92 for a dozen frogs how much would one frog cost Leftwich

Mathematics
2 answers:
blagie [28]3 years ago
6 0

Answer:

$0.41

Step-by-step explanation:

4.92 ÷ 12 = .41 (Look at drawing)

Fofino [41]3 years ago
5 0

Answer:0.41¢

Step-by-step explanation:

$4.92 ÷12= 0.41¢

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The rental fee for space at a flea market is $200 per month base rate
Lesechka [4]

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3 years ago
Consider f(x)=x+7 and g(x)=x^2-1 find (g of f)(x)
finlep [7]

Answer:

g(f(x))=x^2 + 14x + 48

Step-by-step explanation:

you insert (x+7) into every x in the g(x) equation, so g(x)=(x+7)^2 - 1. then you simplify it by doing (x+7)(x+7) which gets you x^2 + 14x + 49. then you subtract the 1 from the equation to get g(f(x))=x^2 + 14x + 48.

6 0
3 years ago
Read 2 more answers
Determine the slope of a line perpendicular to the line with equation 6x-4y= 30
UNO [17]
6x - 4y = 30
-4y = -6x + 30
y = 3/2x - 15/2....slope here is 3/2. A perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So ur perpendicular line will have a slope of -2/3 (see how I flipped 3/2 making it 2/3...and then changed the sign, making it -2/3)

answer : perpendicular line will have a slope of -2/3.
3 0
3 years ago
Read 2 more answers
What is the sum of the first five terms of a geometric series with a1 =20 and r =1/4?
drek231 [11]
The sum of the first n terms in a geometric sequence given the first term (a1) and the common ratio (r) is calculated through the equation,

                            <span>Sn </span>= (<span><span><span>a1</span>(1−<span>r^n</span>) / (</span><span>1−r)

Substituting the known terms,
                           Sn = (20)(1 - (1/4)^4)) / (1 - 1/4)
                           Sn = 26.5625

Thus, the sum of the first four terms is 26.5625. </span></span>
5 0
3 years ago
Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx
shutvik [7]

\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)

Let v=x+y, so that \dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}:

\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1

Now the ODE is separable, and we have

\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx

Integrating both sides gives

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx

For the integral on the left, rewrite the integrand as

\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v

Then

\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C

and so

\csc v-\cot v=x+C

\csc(x+y)-\cot(x+y)=x+C

Given that y(0)=\dfrac\pi2, we find

\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1

so that the particular solution to this IVP is

\csc(x+y)-\cot(x+y)=x+1

5 0
3 years ago
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