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3 years ago

What is the slope of a line perpendicular to the with equation y=6x+2? A.6 B.-6 C.-1/6 D.2

2 answers:

8 0

The equation y = 6x + 2 is in the format which is called the slope-intercept form: y = mx + b where m = slope. Therefore the slope here is 6.
For the line perpendicular, the slope of it is a negative reciprocal from the original slope, that is m(perpendicular) = -1/m

Slope the line perpendicular is m(perpendicular) = -1/6. The answer is C.

Tju [1.3M]3 years ago

8 0

The correct answer is C. -1/6, because (-1/6)* (6)= -1.

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Find the slope of the line that passes through the points (-4, 3) and (6, -2).

Norma-Jean [14]

Answer:

-1/2

Step-by-step explanation:

using the slope formula 3-(-2)/-4-6=-1/2

5 0

3 years ago

Read 2 more answers

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

4 0

3 years ago

DO Tuesday Write 1,003,498 in each form. Word: Expanded: need help really please

alukav5142 [94]

word form: one million, three thousand, four hundred ninety eight

number form : 1,003,498

expaned form 1000000 + 30000 + 400 + 90 + 8

i would so base form but i cant

8 0

2 years ago

PLZ HELP ASAP AREA OF A SECTOR

timama [110]

The relationship of arcs is:
S '/ S = ((1/9) * pi * r) / (2 * pi * r)
Rewriting we have:
S '/ S = ((1/9)) / (2)
S '/ S = 1/18
Therefore, the area of the shaded region is:
A '= (S' / S) * A
Where A: area of the complete circle:
Clearing we have:
A = (A ') / (S' / S)
Substituting:
A = ((1/2) pi) / (1/18)
A = ((18/2) pi)
A = (9pi)
Answer:
The area of the circle is:
A = (9pi)

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3 years ago

The speed of a race car in mph Discrete or continuous

Maru [420]

Answer:

Step-by-step explanation:

Discrete variables are those that can take only a finite number of values. This is not so for speed of an airplane. as it changes from time to time

4 0

3 years ago

Read 2 more answers