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Elden [556K]
3 years ago
13

What is the sum of areas of the faces on a rectangular prism called

Mathematics
1 answer:
stepladder [879]3 years ago
4 0

Answer:

The surface area of the rectangular prism.

Step-by-step explanation:

The formula for the surface area of a rectangular prism is SA = 2 (wl + hl + hw), which actually represents the areas of each of the faces.

SA = 2wl + 2hl + 2hw

We see that the SA is the sum of the areas of the faces on a rectangular prism. Look at a picture of a rectangular prism if you have trouble understanding this.

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(03.01 LC)<br><br> What is the length of leg y of the right triangle? (1 point)
EastWind [94]

Answer:

<h2>A</h2>

Step-by-step explanation:

The complete question is

What is the length of leg y of the right triangle?

A right triangle with hypotenuse 26 and legs 24 and y

  • 10
  • 14
  • 24
  • 26

We need to use the Pythagorean Theorem, where h=26 and x=24,

h^{2} =x^{2} +y^{2}\\ 26^{2}=24^{2}+y^{2}\\y=\sqrt{26^{2}-24^{2}}\\ y=\sqrt{676-576}\\ y=\sqrt{100}\\ y=10

Therefore, the right answer is A. The length of the missing leg is 10 units.

4 0
3 years ago
Can someone pwease help mwe wit dis?
Talja [164]

Step-by-step explanation:

4 * 7 = 28

28 - 12 = 16

4 0
3 years ago
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The graph shows the relationship between the price of frozen yogurt and the number of ounces of frozen yogurt sold at different
snow_lady [41]

Answer:

13

Step-by-step explanation:

If you look at where $5 crosses the line of best fit, you see it between 12 and 14 ounces. The answer is 13.

3 0
3 years ago
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PLATO USERS NEEDED - 50 POINTS
rusak2 [61]
The answer is 2 because you multiply 9.8 times the mass and that will give you your answer
6 0
4 years ago
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A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21
sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{340119}{10} = 34011.9

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

S.D = \sqrt{\frac{2711418821}{9}} = 17357.09

Confidence interval:

\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621

34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)

7 0
3 years ago
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