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3 years ago

9

Read below. I need help

2 answers:

Sauron [17]3 years ago

5 0

Answer:

I would say B

Step-by-step explanation:

Oksana_A [137]3 years ago

5 0

It is b because none of the coordinates mych

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Recess began at 11:12am. It ended at 11:44am. How long was recess?

Soloha48 [4]

Answer:

32 minutes

Step-by-step explanation:

44-12=32

8 0

2 years ago

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For the values a = 3.4 and b = 2.6, which are legs of a right triangle, find c, the hypotenuse, to the nearest tenth.

sammy [17]

C^2 = a^2 + b^2
c^2 = 3.4^2 + 2.6^2
c^2 = 11.56 + 6.76
c^2 = 18.32
c = 4.3

answer
c = 4.3

4 0

3 years ago

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Solving linear equations

AlexFokin [52]

Answer:

(x, y ) = ( $\frac{1}{2}$ , $\frac{5}{2}$ )

Step-by-step explanation:

given the 2 equations

4x + 2y = 7 → (1)

y = 5x → (2)

Substitute y = 5x into equation (1)

4x + 2(5x) = 7

4x + 10x = 7

14x = 7 ( divide both sides by 14 )

x = $\frac{7}{14}$ = $\frac{1}{2}$

substitute this value into equation (2)

y = 5 × $\frac{1}{2}$ = $\frac{5}{2}$

4 0

2 years ago

What is the other square root of 119 + 120i?

MakcuM [25]

Answer:

$\sqrt{119+120 i}=\pm (12.24+i 4.90)$

Step-by-step explanation:

Given

z = 119 + 120 i

Let $\sqrt{119+120 i}=p+iq$

Squaring both sides

$119+120 i=p^2-q^2+2ipq$

Comparing real and imaginary part

Re(LHS)=Re(RHS)

$119=p^2-q^2$ ...........................(1)

comparing Im(LHS)=Im(RHS)

120=2pq

$q=\frac{60}{p}$

Substitute q in 1

$119=p^2-(\frac{60}{p})^2$

$p^4-119p^2-(68)^2=0$

Let $x=p^2$

$x^2-119x-4624=0$

$x=\dfrac{119\pm \sqrt{119^2+4\times 4624}}{2}$

$x=\frac{119\pm 180.71}{2}$

we take only Positive value because $p^2=x$

x=149.85

$p^2=149.85$

thus $p=\pm 12.24$

$q=\pm 4.90$

thus,

$\sqrt{119+120 i}=\pm (12.24+i 4.90)$

8 0

2 years ago

Circumference of 6cm ? help plz <3 heyyy b a e (bet you won't reply :)

Naily [24]

Answer:

If r = 6 cm, the the circumference is c = 2π(6) = 12π cm

HOPE THIS HELPS AND PLS MARK AS BRAINLIEST

THNXX :)

7 0

2 years ago