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Vlad [161]
4 years ago
5

The perimeter of a rectangle is 22 inches. Find the dimensions if its length is 3 inches greater than its width.

Mathematics
1 answer:
MaRussiya [10]4 years ago
7 0

Answer:

Length: 7

Width: 4

Step-by-step explanation:

We can create a system of equations for this problem, where w is the width and l is the length.

The perimeter of a rectangle is twice its length added to twice its width.

2l+2w=22

The length is 3 more than the width:

l = w+3

We can now substitute in w+3 as l in the equation 2l+2w=22.

2(w+3) + 2w = 22

Distribute the first terms:

2w+6+2w=22

Combine like terms:

4w+6=22

Subtract 6 from both sides:

4w=16

Divide both sides by 4:

w = 4

Now we know that w = 4. We can now substitute this inside an equation to find l.

l = w+3\\\\l = 4+3\\\\l=7

Hope this helped!

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6 0
3 years ago
A rectangle has length 72 cm and width 56 cm. The other rectangle has the same area as this one, but its width is 21 cm. What is
katovenus [111]

Answer:

The constant of variation is 4032

Step-by-step explanation:

Given:  

Let a rectangle (say A) has length of rectangle(l)= 72 cm and width of rectangle(w) = 56 cm.

Area of rectangle is multiply its length by its width.

Then,

area of rectangle (A) =l \times w = 72 \times 56 = 4,032 square cm.

It is given that the other rectangle B has the same area as the rectangle A.

Then, the area of rectangle (B) = area of rectangle (A) = 4,032 square cm.  .......[1]

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Divide 21 both sides we get;

l =\frac{4032}{21} = 192 cm

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if y varies inversely as x

i.e, y \propto \frac{1}{x}

⇒ y = \frac{k}{x} where k is the constant variation.

or k = xy

As area of rectangle is multiply its length by width.

This is the inversely variation.

as: l \propto \frac{1}{w}

or l = \frac{A}{w} where A is the constant of variation

Since, the area (A) of both the rectangles are constant.

therefore, the constant of variation is, 4032


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