Question

The perimeter of a rectangle is 22 inches. Find the dimensions if its length is 3 inches greater than its width.

Answer 1

Answer:

Length: 7

Width: 4

Step-by-step explanation:

We can create a system of equations for this problem, where $w$ is the width and $l$ is the length.

The perimeter of a rectangle is twice its length added to twice its width.

$2l+2w=22$

The length is 3 more than the width:

$l = w+3$

We can now substitute in $w+3$ as $l$ in the equation $2l+2w=22$.

$2(w+3) + 2w = 22$

Distribute the first terms:

$2w+6+2w=22$

Combine like terms:

$4w+6=22$

Subtract 6 from both sides:

$4w=16$

Divide both sides by 4:

$w = 4$

Now we know that w = 4. We can now substitute this inside an equation to find $l$.

$l = w+3\\\\l = 4+3\\\\l=7$

Hope this helped!