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Harrizon [31]
3 years ago
14

A spreadsheet keeps track of student scores on all the exams in a course. Each row of the spreadsheet corresponds to one student

, and each column in a row corresponds to his/her score on one of the exams. There are r students and c exams, so the spreadsheet has r rows and c columns.Consider an algorithm that computes the total score on all exams for each student, and the average class score on each exam. You need to analyze the running time of this algorithm.A. What are the basic operations you would count toward the running time?B. What is the worst-case running time as a total count (not big O) of these basic operations?C. What is the big O running time?D. Is your algorithm linear, quadratic, or some other order?
Computers and Technology
1 answer:
vivado [14]3 years ago
7 0

Answer:

Check the explanation

Explanation:

A. The fundamental or basic operations are addition and division.

B. The total figure for each student (which starts at 0) will be included to c times. Given that there are r student totals, there are <em>r*c</em> additions for the totals. (An optional correct answer is <em>r*(c-1)</em> if you begin the accumulator with the initial item in a column, and perform <em>(c-1)</em> additions.)

Each exam average will be included to r times. In view of the fact that there are c exams, this gives another <em>c*r</em> additions.

All the exam average will be divided exactly once by the amount of students, c. So, c divisions.

C. <em>O(rc) </em>

D. LINEAR (Note: The Big O appears like a quadratic value, although the INPUT SIZE is rc, and the running time is linearly relative to the input size.)

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What are the assignable addresses for the 12th subnet with the network address of 220.100.100.0 and the number of needed subnets
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C. 220.100.100.45 to 220.100.100.46

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The Classless IP subnetting of 220.100.100.0 begins from the fourth octet of the IP address. To get 45 subnet mask, it uses 6 bits from the fourth octet, which approximately give 64 subnets, while the remaining 2 bits are used for host IP addressing.

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While the 12th subnet is 12 x 2^2 = 44.

This means that the 12th subnet mask starts with 220.100.100.44 (as the network address) and ends with 220.100.100.47 as broadcast IP address, while '.45' and '.46' are the assignable addresses of the subnet.

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What part of a resource record tells a server how long the record should remain in the cache?
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Given that it takes 0.08 ms to travel from one track to the next of a hard drive; that the arm is originally positioned at Track
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Time taken to travel from one track to the next = 0.08ms

Initial track= 15     0

4      (15-4)*(0.08)= 0.88

40     (40-4)*(0.08)= 2.88

35      (40-35)*(0.08)= 0.4

11       (35-11)*(0.08)= 1.92

14       (14-11)*(0.08)= 0.24

7         (14-7)*(0.08)= 0.56

----------------------------------------------

Total seek time=0.88+2.88+0.4+1.92+0.24+0.56=6.88ms

Explanation:

We caculate the seek time for each request, and then add them together to find the total seek time. The final track number for the current request becomes the current track of next request, and this process is repeated till the last request is processed.

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