Answer:
#include <bits/stdc++.h>
using namespace std;
int main() {
string email,username,host;//strings to store email,username,hostname..
cout<<"Enter the email address "<<endl;
cin>>email;//taking input of email address..
bool flag=1;
for(int i=0;i<email.length();i++)//iterating over the string email..
{
if(email[i]=='@')//if @ symbol is encountered make flag 0 skip this iteration.
{
flag=0;
continue;
}
if(flag==1)//add to username if flag is 1.
{
username+=email[i];
}
else//add tom host..
host+=email[i];
}
cout<<"The username is "<<username<<endl<<"The host name is "<<host;//printing the username and hostname..
return 0;
}
Explanation:
I have taken three strings to store the email address entered by user ,username and host to store username and host name respectively.Then I am iterating over the string email if @ is encountered then skip that iteration before that keep adding characters to username string and after that keep adding characters to host.
Answer:
3
Explanation:
MOD means the remainder after a division calculation.
The remainder is 3
Answer: D) Identifying GUI's for a particular requirement
Explanation:
Traceability of requirements is helpful except identifying GUI's for a particular requirements as, traceability in project management describe the relationships between two or more element throughout in the development process and outline the relationship between the customer requirement by traceability matrix. And the requirement of traceability is so important because it creating a downstream flow of software and test cases in software requirement but not helpful in GUI identification.
Answer:
Following is the program in C++ Language
#include <iostream> // header file
using namespace std; // namespace std
int main() // main method
{
int n; // variable declaration
cout<<" Please enter the number :";
cin>>n; // Read the number
if(n>0) // check the condition when number is positive
{
cout<<n<<endl<<"The number is Positive"; // Display number
}
else if(n<0) // check the condition when number is Negative
{
cout<<n<<endl<<"The number is Negative";// Display number
}
else // check the condition when number is Zero
{
cout<<n<<endl<<"The number is Zero";// Display number
}
return 0;
}
Output:
Please enter the number:
64
The number is Positive
Explanation:
Following are the description of the program
- Declared a variable "n" of int type.
- Read the value of "n" by user.
- Check the condition of positive number by using if block statement .If n>0 it print the number is positive.
- Check the condition of negative number by using else if block statement If n<0 it print the number is negative.
- Finally if both the above condition is fail it print the message " The number is Zero"
Lowercase a is decimal 97 ; upper case is decimal 65
It's easier to think of them in octal, however: a = octal 141, and A is octal 101
octal to binary is easy, each digit is three bits.
141 = 001 100 001
101 = 001 000 001
So, how many bits are changed above?
